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Jet001 [13]
3 years ago
12

How many pounds of chamomile tea that costs 18.20 per pound must be mixed with 16 Ib of orange tea that costs 12.22 per pound to

make a mixture that cost 14.52 per pound
Mathematics
2 answers:
Law Incorporation [45]3 years ago
5 0

Answer: the number of pounds of chamomile tea that must be mixed is 10

Step-by-step explanation:

Let x represent the number of pounds of chamomile tea that must be mixed.

The chamomile tea costs 18.20 per pound. This means that the cost of x pounds is 18.2 × x = 18.2x

The orange tea costs 12.22 per pound. This means that the cost of 16 pounds would be

16 × 12.22 = 195.52

The mixture costs 14.52 per pound. This means that the total cost of the mixture made is

14.52(16 + x)

Therefore

18.2x + 195.52 = 14.52(16 + x)

18.2x + 195.52 = 232.32 + 14.52x

18.2x - 14.52x = 232.32 - 195.52

3.68x = 36.8

x = 36.8/3.68

x = 10

Oxana [17]3 years ago
4 0

Answer:

10 pounds

Step-by-step explanation:

C = pounds of chamomile tea

O = pounds of orange tea

X = pounds

C * 18.20 + 0*12.22 = X * 14.52

0 = 16 lb

we propose an equation about the amount of money that will come out and another equation only with the liters that will be

C * 18.20 + 16*12.22 = X * 14.52

18.20C + 195.52 = 14.52X

14.52X - 18.20C = 195.52

C + 0 = X

C + 16 = X

14.52(C + 16) - 18.20C = 195.52

14.52C + 232.32 - 18.20 = 195.52

14.52C - 18.20 = 195.52 - 232.32

-3.68C = -36.8

C = -36.8/-3.68

C = 10

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