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Alja [10]
2 years ago
12

Ms. Carey grades 4 tests during her lunch. She grades 1/3 of the remainder after school. If she syill5has 16 test to grade after

school, how many test are there?
​
Mathematics
1 answer:
enot [183]2 years ago
3 0

Answer: 24 tests

Step-by-step explanation:

Ms. Carey graded 1/3 of the tests and still had 16 tests to go.

This means that the 16 tests represent the remaining proportion of the total number of tests:

= 1 - 1/3

= 2/3

2/3 of the total is equal to 16 tests. Assuming the total is x, the expression would be:

2/3x = 16

x = 16 ÷ 2/3

x = 16 * 3/2

x = 24 tests

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Alik [6]

Answer:

2cm of Rainfall

Step-by-step explanation:

When the no. of mosquitoes is the highest the slope of graph will be zero

so if we differentiate this function and equate to zero we can find the rainfall amount that gives maximum number of mosquitoes in centimetres.

m(x)= -x²+4x

differentiate

d(x)/d(m(x))= -2x+4

equate to zero

-2x+4=0

2x=4

x=2

answer: 2 cm of rain

6 0
2 years ago
Graph the following function: y=3x-5
patriot [66]

(0,-5) and (3,-4)                                                                                                                               Hope this helps

4 0
3 years ago
How do you simplify the expression
zepelin [54]
PEMDAS
12-14=-2
-2-5=-7
-7-9=-16
-16-4=-20
-20 is the answer
5 0
3 years ago
Read 2 more answers
If there is 24 apple in total and there is 6 apples that are bad what is the percentage of the apples that are bad
il63 [147K]

Answer:

6 is 25% of 24.

Step-by-step explanation:

6 ÷ 24 = 0.25 = 25%

8 0
2 years ago
Suppose m is the line with equation y = −4 and ΔA'B'C is mapped to ΔA"B"C" by applying the glide reflection T3, 0 Rm.
balandron [24]

Answer:

The coordinates of ΔA''B''C'' are;

A''(-1, -3), B''(-2, -6), C''(1 , -7)

Step-by-step explanation:

A glide reflection involves the reflection of the preimage over a given line, followed by the translation of the resulting image along the given line

Given that the coordinates of the triangle ΔA'B'C' are;

A'(-4, -5), B'(-5, -2), C'(-2, -1), we have by reflection across the line y = -4

A''(-4, -4 + 1) = A''(-4, -3)

B''(-5, -4 - 2) = B''(-5, -6)

C''(-2, -4-3) = C''(-2, -7)

Translation of A''B''C'' by T 3, 0, we have;

A''(-4, -3)  → T₃, ₀ → A''(-4 + 3, -3) = A''(-1, -3)

B''(-5, -6)  → T₃, ₀ → B''(-5 + 3, -6) = B''(-2, -6)

C''(-2, -7) → T₃, ₀ → C''(-2 + 3, -7) = C''(1 , -7)

The coordinates of ΔA''B''C'' are therefore;

A''(-1, -3), B''(-2, -6), C''(1 , -7).

5 0
3 years ago
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