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Alja [10]
2 years ago
12

Ms. Carey grades 4 tests during her lunch. She grades 1/3 of the remainder after school. If she syill5has 16 test to grade after

school, how many test are there?
​
Mathematics
1 answer:
enot [183]2 years ago
3 0

Answer: 24 tests

Step-by-step explanation:

Ms. Carey graded 1/3 of the tests and still had 16 tests to go.

This means that the 16 tests represent the remaining proportion of the total number of tests:

= 1 - 1/3

= 2/3

2/3 of the total is equal to 16 tests. Assuming the total is x, the expression would be:

2/3x = 16

x = 16 ÷ 2/3

x = 16 * 3/2

x = 24 tests

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Is there a faster way to find GCF of large numbers e.g 828 and 529.
Sunny_sXe [5.5K]
You can use prime factorization to find the GCF of a set of numbers. This often works better for large numbers, where generating lists of all factors can be time-consuming.
Here’s how to find the GCF of a set of numbers using prime factorization:
* List the prime factors of each number.
* Circle every common prime factor — that is, every prime factor that’s a factor of every number in the set.
* Multiply all the circled numbers.
The result is the GCF.
For example, suppose you want to find the GCF of 28, 42, and 70. Step 1 says to list the prime factors of each number. Step 2 says to circle every prime factor that’s common to all three numbers (as shown in the following figure).
As you can see, the numbers 2 and 7 are common factors of all three numbers. Multiply these circled numbers together:
2 · 7 = 14
Thus, the GCF of 28, 42, and 70 is 14.

5 0
2 years ago
Asking costs 5 points and then choosing a best answer earns you 3 points!
yKpoI14uk [10]
Thanks this came in handy bc I'm a beginner
4 0
3 years ago
Nicole used 3/8 of her ribbon to wrap the present. If she used 6 feet of ribbon for the present how much ribbon did Nicole have
lilavasa [31]
You would set up a proportion. 3/8 = 6/x... cross multiply ( 3*x = 3x and 6*8 = 48)  3x = 48... divide both sides by 3 (3x/3 = x and 48/3 = 16)

So, she originally had 16 feet of ribbon.
6 0
3 years ago
5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g
anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1117}{10} = 111.7

Sum of squares of differences = 642.1

S.D = \sqrt{\frac{642.1}{49}} = 8.44

We are given the following in the question:  

Population mean, μ = 106

Sample mean, \bar{x} = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

H_{0}: \mu = 106\\H_A: \mu > 106

We use one-tailed(right) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833

Since,                  

t_{stat} > t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0
3 years ago
Given the following functions f(x) and g(x), solve f over g(−4) and select the correct answer below:
marishachu [46]
\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\f(x)=4x-4;\ g(x)=x-1\\\\f(-4)=4\cdot(-4)-4=-16-4=-20\\\\g(-4)=-4-1=-5\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{-20}{-4}=4
5 0
3 years ago
Read 2 more answers
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