Answer:
Two hundred would be appropriate for a random sample.
Answer:
Q1: 77°, Q2: 103°, Q3: 257°, Q4: 283°
Step-by-step explanation:
Note: Q1 = Quadrant 1
Q1: 77°
Q2: 180° - 77° = 103°
Q3: 180° + 77° = 257°
Q4: 360° - 77° = 283°
Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
![\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B100%7Dx%2B%5Cfrac%7B6%7D%7B100%7D%286000-x%29%3D337.5%20%20%20)
Multiplying both sides by 100 we get:
![5x+6(6000-x)=33750](https://tex.z-dn.net/?f=%205x%2B6%286000-x%29%3D33750%20)
![5x+36000-6x=33750](https://tex.z-dn.net/?f=%205x%2B36000-6x%3D33750%20)
Subtracting both sides by 36000 we get:
![-x=-2250](https://tex.z-dn.net/?f=%20-x%3D-2250%20)
![\therefore x=2250](https://tex.z-dn.net/?f=%20%5Ctherefore%20x%3D2250%20)
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Only x-intercept because if you want to know about x-intercepts so y will be zero (y=0)
then 0 =4x^2 -12x + 9
0=(2x-3)(2x-3)
0=2x-3
so x=3/2 that is x-intercept