Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = ![\dfrac{10+11}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B10%2B11%7D%7B2%7D)
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
20 % = 225
1% = 225 / 20
100% = 225 * 100 / 20
= 1125 answer
Answer:
26
Step-by-step explanation:
10+(10x3)-2(10-3)=
10+30+-2(7)=
40-14=
26
If we let x as the number of years of service in the company and f(x) as the increase in the wage, the step wise function that describes the scenario is
f(x) = { 0.5, x < 3
{ 1.0, 3 ≤ x < 6
{ 1.5, 6 ≤ x < 9
{ 2.0, 9 ≤ x < 12
The point (2, 12) represents the wage increase of x < 12
Answer:
1/2: the fourth quadrant
3/4:"Q1: 4,5" "Q2: 4,-1" "Q3: -2,-3" "Q4: 5, -2"
Step-by-step explanation:
hope this helps!