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algol13
4 years ago
13

Solve each quadratic equation. Problem: (2x – 1)(x + 7) = 0 Answer: x= ½, -7

Mathematics
1 answer:
Afina-wow [57]4 years ago
8 0
(2x-1)(x+7) = 0

2x-1=0
2x =1
x = 1/2

x+7=0
x = -7
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The budgeted amount for a year for a medication is $1800. What is the budgeted amount for each month?
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4 years ago
Simplify the given expression 8x^2-8/ x / 8(x^2 + 8)/26x^2 - 31x
notsponge [240]

Answer:

-x • (x2 - 208x + 814)

 ——————————————————————

           26          

Step-by-step explanation:

Step  1  :

           x2 + 8

Simplify   ——————

             26  

Polynomial Roots Calculator :

  Find roots (zeroes) of :       F(x) = x2 + 8

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  8.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,4 ,8

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        9.00      

     -2       1        -2.00        12.00      

     -4       1        -4.00        24.00      

     -8       1        -8.00        72.00      

     1       1        1.00        9.00      

     2       1        2.00        12.00      

     4       1        4.00        24.00      

     8       1        8.00        72.00      

Polynomial Roots Calculator found no rational roots

Equation at the end of step  1  :

             8     (x2+8)

 ((8•(x2))-((— ÷ 8•——————)•x2))-31x

             x       26  

:

           8

Simplify   —

           x

Equation at the end of step  2  :

             8     (x2+8)

 ((8•(x2))-((— ÷ 8•——————)•x2))-31x

             x       26  

        8      

Divide  —  by  8

        x      

             1 (x2+8)

 ((8•(x2))-((—•——————)•x2))-31x

             x   26  

Equation at the end of step  4  :

                 (x2 + 8)            

 ((8 • (x2)) -  (———————— • x2)) -  31x

                   26x                

Dividing exponential expressions :

 x2 divided by x1 = x(2 - 1) = x1 = x

Equation at the end of step  5  :

                x • (x2 + 8)      

 ((8 • (x2)) -  ————————————) -  31x

                     26          

Equation at the end of step  6  :

          x • (x2 + 8)      

 (23x2 -  ————————————) -  31x

               26          

Rewriting the whole as an Equivalent Fraction :

  Subtracting a fraction from a whole

Rewrite the whole as a fraction using  26  as the denominator :

            23x2     23x2 • 26

    23x2 =  ————  =  —————————

             1          26    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

    Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

23x2 • 26 - (x • (x2+8))      -x3 + 208x2 - 8x

————————————————————————  =  ————————————————

           26                       26        

Equation at the end of step  7  :

 (-x3 + 208x2 - 8x)    

 —————————————————— -  31x

         26            

Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  26  as the denominator :

          31x     31x • 26

   31x =  ———  =  ————————

           1         26    

Pulling out like terms :

   Pull out like factors :

  -x3 + 208x2 - 8x  =   -x • (x2 - 208x + 8)  

Trying to factor by splitting the middle term

     Factoring  x2 - 208x + 8  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -208x  its coefficient is  -208 .

The last term, "the constant", is  +8  

Multiply the coefficient of the first term by the constant   1 • 8 = 8  

Find two factors of  8  whose sum equals the coefficient of the middle term, which is   -208 .

     -8    +    -1    =    -9  

     -4    +    -2    =    -6  

     -2    +    -4    =    -6  

     -1    +    -8    =    -9  

     1    +    8    =    9  

     2    +    4    =    6  

     4    +    2    =    6  

     8    +    1    =    9  

Adding fractions that have a common denominator :       Adding up the two equivalent fractions

-x • (x2-208x+8) - (31x • 26)     -x3 + 208x2 - 814x

—————————————————————————————  =  ——————————————————

             26                           26        

Pulling out like terms :

10.1     Pull out like factors :

  -x3 + 208x2 - 814x  =   -x • (x2 - 208x + 814)  

Trying to factor by splitting the middle term

10.2     Factoring  x2 - 208x + 814  

The first term is,  x2  its coefficient is  1 .

The middle term is,  -208x  its coefficient is  -208 .

The last term, "the constant", is  +814  

Multiply the coefficient of the first term by the constant   1 • 814 = 814  

Find two factors of  814  whose sum equals the coefficient of the middle term, which is   -208 .

     -814    +    -1    =    -815  

     -407    +    -2    =    -409  

     -74    +    -11    =    -85  

     -37    +    -22    =    -59  

     -22    +    -37    =    -59  

     -11    +    -74    =    -85  

     -2    +    -407    =    -409  

     -1    +    -814    =    -815  

     1    +    814    =    815  

     2    +    407    =    409  

     11    +    74    =    85  

     22    +    37    =    59  

     37    +    22    =    59  

     74    +    11    =    85  

     407    +    2    =    409  

     814    +    1    =    815  

5 0
3 years ago
It also detects if you are right or wrong
garik1379 [7]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

According to the table ;

f(0) = 6

Let's check that in which of the equations it happens.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

A )

y = f(x) = 6x + 4

f(0) = 6(0)  + 4

f(0) = 0 + 4

f(0) = 4

Wrong

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

B )

y = f(x) = 4x + 6

f(0) = 4(0) + 6

f(0) = 0 + 6

f(0) = 6

Correct.

Thus this option is the correct answer.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

C )

<em>y = f(x) = 2x + 4</em>

<em>f(0) = 2(0) + 4</em>

<em>f(0) = 0 + 4</em>

<em>f(0) = 4</em>

Wrong

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
3 years ago
the catalogue price of an article is rs.50000 and a manufacturer sells it to the distributor at a discount of 20% of the catalog
timofeeve [1]

Answer:

A. what is the profit made by the retailer if he sells the article to the customer at the catalogue price?

10000

B.What profit is made by the manufacturer if the catalogue price is 50% above the manufacturing price?

25000

7 0
3 years ago
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