Write an expression of the verbal phrase: the quotient of twelve and the product of three times x

Simplify.(6x−5+4x^2)+(2x−2)

leonid [27]

Combine Like Terms

=6x + −5 + 4 x 2 + 2x + −2

=(4 x 2) + (6x + 2x) + (−5 + −2)

=4 x 2 +8x + −7

Answer - 4 x 2 + 8x + −7

7 0

3 years ago

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Find X please help me with test corrections due midnight tonight!<br>If HBN is congruent to LYR.

kkurt [141]

Step-by-step explanation:

here's the solution: -

if the given triangles are similar, then their corresponding sides will be in proportion, so

=》

$\frac{x}{14} = \frac{x + 11}{21}$

( by cross multiplication )

=》

$21x = 14x + 154$

=》

$21x - 14x = 154$

=》

$7x = 154$

=》

$x = \frac{154}{7}$

=》

$x = 22$

8 0

3 years ago

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The table and the graph show information about students enrolled in spanish and french classes at a high school. use the graph t

Archy [21]

Answer:

after 6 years

Step-by-step explanation:

thats when the lines intersect, (6,300)

5 0

3 years ago

Find the solution of the following simultaneous inequalities: x - 7 –1

Zinaida [17]

Answer:

x-8

Step-by-step explanation:

You add the -7 and -1 and then put the x in front of your answer.

7 0

3 years ago

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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago