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3 years ago

Y = -x + 3 X+ y=20 Are the lines parallel?

Mathematics

1 answer:

diamong [38]3 years ago

8 0

Answer:

Yes

Step-by-step explanation:

If we put both equations in slope-intercept form, we have

y=-x+3

y=-x+20

Both lines have the same slope of (-1).

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What is the area of 10mm 7mm and 16mm

sleet_krkn [62]

Step-by-step explanation:

Area=10*7*16mm³=1120mm³

5 0

3 years ago

Read 2 more answers

A forest fire covers 2006 acres at time t equals 0. the fire is growing at a rate of 8 startroot t endroot acres per hour, where

MissTica

<span>Answer: We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start. A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24) A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24) A = 2010 + 627 = 2637 acres We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>

8 0

3 years ago

Identify the slope and y-intercept of the function y = -2x + 3. O A. The slope is 3. The y-intercept is (0,2). OB. The slope is

monitta

Since the slope-intercept form of a line is given by the expression:

$y=mx+b$

Where, m is the slope and b is the y-intercept.

Then, for the function:

$y=-2x+3$

The slope is -2 and the y-intercept is (0, 3)

7 0

1 year ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

How is a finance charge calculated

GuDViN [60]

Answer:

option A. Multiply the unpaid balance by the monthly interest rate

Step-by-step explanation:

Finance charges are the monthly service fee charged by lender on the credit used by borrower if they wish to skip the payment of monthly bill and carry forward it to next month.

So, we can calculate finance charges as monthly interest accrued on the unpaid balance.

Finance charges = Unpaid balance x Monthly interest rate.

Hence, option A is correct, i.e. Multiply the unpaid balance by the monthly interest rate.

6 0

4 years ago