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3 years ago

8

Janet is 48 in tall and Lucy her younger sister is 32 in tall at 2:30 in the afternoon Lucy's Shadow extends 34 in how far does

Janet's Shadow extend at 2:30 in the afternoon

1 answer:

Elis [28]3 years ago

5 0

Janet is 50inches tall.

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Hi everone can you help i will be sending more qusetions each one is 10 points thank you

kkurt [141]

Answer:

144 cubic inches

Step-by-step explanation:

volume = l x w x h. This = 8 x 6 x 3.

Hope this helps :)

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2 years ago

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27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8

Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

$27^x=9^{x-4}$

Note that

$27=3^3\\ \\9=3^2,$

then

$27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}$

Rewrite the equation as

$3^{3x}=3^{2(x-4)},$

then

$3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8$

4 0

3 years ago

there are 2 1\2 bus loads of students standing in a parking lot. The students are getting ready to go on a field trip. 2\5 of th

Archy [21]

It would take only one full bus to carry only girls.

3 0

3 years ago

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What is the measurement of two-fifths of a right angle?

barxatty [35]

36.

90 times 2/5 (or 0.4) is equal to 36

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3 years ago

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What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?

Pani-rosa [81]

Answer: The required fourth term of the geometric sequence is $\dfrac{10}{9}.$

Step-by-step explanation: We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

$a(1)=30,~~~~~r=\dfrac{1}{2}.$

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

$a(n)=a(1)r^{n-1}.$

Therefore, the fourth term of the given geometric sequence will be

$a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.$

Thus, the required fourth term of the geometric sequence is $\dfrac{10}{9}.$

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3 years ago

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