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wolverine [178]
3 years ago
10

The width of a certain rectangle is 75% of its length. The perimeter of the rectangle is 148 centimeters. What are the dimension

s of the rectangle?

Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0
I only suppose this is the right answer

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Seven times a number is the same as 12 more than 3 times the number
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Answer:

x=3

Step-by-step explanation:

7x=12+3x

4x=12

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Rectangle STUV is shown on a coordinate plane. Rectangle STUV with vertices S at negative 7 comma 6, T at negative 2 comma 6, U
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The coordinate of the point T after the given transformations is; T''(-2, -4)

<h3>How to carry out Translation Transformations?</h3>

We are given the coordinates of the rectangle STUV as;

S(-7, 6)

T(-2, 6)

U(-2, 1)

V(-7, 1)

Now, we are told that all these coordinates are translated using the transformation rule;  (x, y) → (x − 2, y − 4)

Thus, the new coordinates using this transformation rule are;

S'(-9, 2)

T'(-4, 2)

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Now, we are told that these new points are  rotated 90° counterclockwise and as such the new coordinates formed will follow the pattern (x, y) → (-y, x).

Thus, our final coordinates are;

S''(-2, -9)

T''(-2, -4)

U''(3, -4)

V''(3, -9)

Thus, the coordinate of the point T after the given transformations is; T''(-2, -4)

Read more about Translation Transformation at; brainly.com/question/4289712

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Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
ehidna [41]
<span>Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
</span>\dfrac{x^3+10}{x^3+9}=1+\dfrac{1}{x^3+9} \\ \\ \\  \dfrac{x^3+10}{x^3+9}=\dfrac{(x^3+9)+1}{x^3+9}\\ \\ \\  \dfrac{x^3+10}{x^3+9}=\dfrac{x^3+10}{x^3+9}  \\ \\ \\x\in R \qquad x\in (-\infty, +\infty)<span>
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The interest is 37.7$
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Sixth graders can have 4 groups of 4
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