Cathy measured a room to be 10 1/2 feet by 12 5/8 feet. What is the area of the room

1 answer:

6 0

We know that are for the rectangle is A=a*b, where
A i area, a is one side and b is second side. It doesnt matter side we assume a or b because multiplicity is commutative.
We can substitute our data to formula
A= $10 \frac{1}{2} *12 \frac{5}{8} = \frac{21}{2}* \frac{101}{8}= \frac{21*101}{2*8}= \frac{2121}{16}= 132.56$ [feet squared] - its the answer

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What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

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Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$