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3 years ago

8

Cathy measured a room to be 10 1/2 feet by 12 5/8 feet. What is the area of the room

1 answer:

Masteriza [31]3 years ago

6 0

We know that are for the rectangle is A=a*b, where
A i area, a is one side and b is second side. It doesnt matter side we assume a or b because multiplicity is commutative.
We can substitute our data to formula
A= $10 \frac{1}{2} *12 \frac{5}{8} = \frac{21}{2}* \frac{101}{8}= \frac{21*101}{2*8}= \frac{2121}{16}= 132.56$ [feet squared] - its the answer

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julsineya [31]

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3 years ago

See image for question.

kotegsom [21]

Answer:

<h3>#7</h3>

(a)

<u>Sample space:</u>

1*1, 1*2, 1*3, 1*4,
2*1, 2*2, 2*3, 2*4,
3*1, 3*2, 3*3, 3*4,
4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

(i) P(even) = 12/16 = 3/4
(ii) P(3x) = 7/16
(iii) P(perfect square) = 4/16 = 1/4

<h3>#8</h3>

(a) <u>Sample space:</u>

1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

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(iii) 1H, 2H, 3H, 4H

P(H) = 4/8 = 1/2

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3 years ago

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andreyandreev [35.5K]

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3 years ago

To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x

Fiesta28 [93]

Given function is

$f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.$

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

$kx^2-5$

so RHD= $k(-4)^2-5$

Now set both equal

$k(-4)^2-5=3(-4)+k$

$16k-5=-12+k$

$16k-k=-12+5$

$15k=-7$

$k=-\frac{7}{15}$

k=-0.47

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