There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
I think its adjacent not for sure
Answer:
x = 11.5
Step-by-step explanation:
Taking the logarithm base 2 will transform this to a linear equation.
2(2x+7) = 3(2x -3)
0 = 3(2x -3) -2(2x +7) . . . . subtract the left side
0 = 2x -23 . . . . . . . . . . . . . simplify
0 = x - 23/2 . . . . . . . . . . . . divide by 2
11.5 = x . . . . . . . . . . . . . . . . add 11.5
The solution is x = 23/2 = 11.5.
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<em>Check</em>
This value of x makes the equation become ...
4^(2·23/2 +7) = 8^(2·23/2 -3)
4^30 = 8^20 . . . . . true
There you go. cube root of smth is just the value to the power of one third.
Answer:3 9/20
Step-by-step explanation:
