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frez [133]
3 years ago
14

How do you find the quadratic equation for the roots 3 and 17?

Mathematics
1 answer:
Naily [24]3 years ago
6 0
The roots are 3 and 17 so the distributed equation is

(x-3)(x-17)

distribute 

x²-3x-17x+51

x²-20x+51

I hope I've helped! 
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The Gophers won 2/3 of their games. The Rattlers
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Answer:

48

Step-by-step explanation:

The silmutenous equations

2/3x + 1/2y = 56

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How to write 14.05 in expanded form ?
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You write 10+4+.05.
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Simplify 3(2x^4*y^5)^2/(6x^3*y^3)^6
Thepotemich [5.8K]

\dfrac{3(2x^4y^5)^2}{(6x^3y^3)^6}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{3(2^2)(x^4)^2(y^5)^2}{6^6(x^3)^6(y^3)^6}=\dfrac{3(4)x^8y^{10}}{46656x^{18}y^{18}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{12x^8y^{10}}{46656x^8x^{10}y^{10}y^8}=\dfrac{1}{3888x^{10}y^8}

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3 years ago
Jasmine was asked to find the product of 14.8 and 3.65. Her work is shown below. Estimate: 15 × 4 = 60 Actual: 14.8 × 3.65 = 540
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Answer:

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8 0
3 years ago
Which sequence follows the rule an =an–1 + 7?
Akimi4 [234]

Answer:

A

Step-by-step explanation:

using the rule : a_{n} = a_{n-1} + 7

sequence A with a₁ = 11

a₂ = a₁ + 7 = 11 + 7 = 18

a₃ = a₂ + 7 = 18 + 7 = 25

a₄ = a₃ + 7 = 25 + 7 = 32

sequence A is generated using the rule

sequence B with a₁ = 17

a₂ = a₁ + 7 = 17 + 7 = 24

a₃ = a₂ + 7 = 24 + 7 = 31

a₄ = a₃ + 7 = 31 + 7 = 38

sequence B is not generated using the rule

sequence C with a₁ = - 15

a₂ = - 15 + 7 = - 8

a₃ = a₂ + 7 = - 8 + 7 = - 1

a₄ = a₃ + 7 = - 1 + 7 = 6

sequence C is not generated using the rule

sequence D with a₁ = - 9

a₂ = a₁ + 7 = - 9 + 7 = - 2

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a₄ = a₃ + 7 = 5 + 7 = 12

sequence D is not generated using the rule



7 0
3 years ago
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