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3 years ago

1 If ZA and ZB are complementary angles and mA = 60°, then m B =?

Mathematics

1 answer:

yarga [219]3 years ago

3 0

Answer:

30 degrees

Step-by-step explanation:

Because the angles are complementary, they MUST equal to 90 degrees

Because measure of Angle A = 60, then the measure of Angle B = 30, because 60 + 30 = 90 degrees

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A department store, on average, has daily sales of 28,651.79. the standard deviation pf sales is $1000. On Tuesday, the store so

adelina 88 [10]

Answer:

Tuesday's Z-score is 7.56

Step-by-step explanation:

We are given that a department store, on average, has daily sales of 28,651.79 and the standard deviation of sales is $1000.

Also, it is given that on Tuesday, the store sold $36,211.08 worth of goods.

Let X = Daily sales of goods

So, X ~ N( $\mu = 28,651.79, \sigma^{2} =1000^{2}$ )

The z-score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ standard normal N(0,1)

Now, Tuesday,s Z-score is given by;

Z = $\frac{36,211.08-28,651.79}{1000}$ = 7.56

Yes, Tuesday was an unusually good day as on this day more worth of sales takes place as compared to the average daily sales of $28,651.79 .

5 0

4 years ago

A coin flipped 14 times and it comes up heads 10 times what is the experimental probability of the coin’s coming up heads ?

Gekata [30.6K]

The answer is B.

If a coin is flipped 14 times and lands on heads 10 times the fraction would equal to 10/14.

10/14 simplifies to 5/7.

3 0

3 years ago

Read 2 more answers

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud

SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

$M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }$

The 85% confidence level $z_{\alpha } = 1.44$

$\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}$

$\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}$

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0

3 years ago

Jake drove 300 miles from his house to a soccer tournament. This graph shows the distance Jake had traveled (m) and the time tha

Bad White [126]

Part A. The trip starts at 8am which corresponds to 0 hrs, point (0hr, 0mi)

2hrs later it's 10am. .point (2hr, 140mi)

The average speed is the slope between 0 and 2 hrs. Remember the slope formula m = Δy/Δx

m = (140 - 0) / (2 - 0)

m = 70 mph

Part B. Average speed from 11am - 2pm

11am is point (3hr, 140mi)

2pm is point (6hr, 300mi)

As you can see from the graph, the speed or slope changes at 1pm (5,260). You Can just use the start and end points.

m = (300-140) / (6-3)

m = 160/3

53.3 mph

* It comes out the same solution as if you average the two different slopes. 2hrs at 60mph + 1 hr at 40mph = (120 + 40)/3 = 160/3

Part C. Total average speed = total distance / total time driving

He went 70 mph for 2 hrs

stopped for an hour (slope is zero, no speed)

60 mph for 2hrs

40mph for 1 hr

300mi /5hr = 60mph

Part D. No Question....

7 0

3 years ago

How do you simplify 4^-2h^-4j^3

notka56 [123]

j^3
_______
4^2 h^4

when you have negatives, you want them to be positive. To do that you need to convert it into a fraction

7 0

3 years ago