7/8 4/8 how much farther does 7/8 have than 4/8
1 answer:
You might be interested in
<u>(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)</u>
For this case we must find the value of n of the following equation:
Taking common factor "n" from the left side of the equation we have:
Multiplying by 5 on both sides of the equation:
Dividing between 6 on both sides of the equation:
Thus, the value of n is 20.
Answer: