There are 15children ten children are each wearing 1cap how many more caps would you need to have one cap on each child? Draw to
1 answer:
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The two equations are
and
the first equation can be solved for x to be
next you can substitute x in the second equation
Distribute 4 to everything in the parentheses
combine like terms:
subtract 28 from both sides of the equation
divide both sides by -1.5
plug this in to the original equation of x+y=7
subtract 4 from both sides.
Final Answer: they bought 3 adult tickets and 4 student tickets
Hope this helps!
and
the first equation can be solved for x to be
next you can substitute x in the second equation
Distribute 4 to everything in the parentheses
combine like terms:
subtract 28 from both sides of the equation
divide both sides by -1.5
plug this in to the original equation of x+y=7
subtract 4 from both sides.
Final Answer: they bought 3 adult tickets and 4 student tickets
Hope this helps!