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Vlad1618 [11]
3 years ago
6

Please help !! Picture provided !!!

Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0
Method One
Your calculator might be able to do this. Mine does it like this.
6
nCr
2  
= 
15

Method 2
You could simply set up 6C2

This gives you
\frac{n!}{(n- r)! r!} =  \frac{6!}{(6 - 2)!2!} =  \frac{6!}{4! 2!} =  \frac{6*5}{2*1} = 15

Method Three
You only have to do this a couple of times to see how the cancellation works.

\frac{6!}{4!2!} =  \frac{6*5*\st{4*3*2*1}}{4*3*2*1 * 2*1}
After all the cancellation takes place you have
6*5/2 = 15
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Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
3 years ago
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3 0
3 years ago
2p2 - 5p + 3<br> pliss anwered this for me​
Iteru [2.4K]

Answer:

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Step-by-step explanation:

Wishing you a splendiferous day,

stay salty...

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2 years ago
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Oi  :)

1) There are 3 significant digits
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2)
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