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monitta
2 years ago
15

Mrs. Patterson but a set of building blocks for her son each cube shaped block measured 4 cm on one side what is the volume of s

ix building blocks
Mathematics
1 answer:
dimulka [17.4K]2 years ago
4 0

Given:

The shape of all building blocks is a cube of side 4 cm.

To find:

The volume of six building blocks.

Solution:

Volume of a cube is:

V=a^3

Where, a is the side length of the cube.

Putting a=4, we get

V=(4)^3

V=64

It means the volume of each building block is 64 cubic cm.

Now, the volume of six building blocks is

Volume=6\times V

Volume=6\times 64

Volume=384

Therefore, the volume of six building blocks is 384 cubic cm.

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The volume of a cylinder is 256 in height of the cylinder is 1 in. What is the radius of the​ cylinder?
Sindrei [870]

Answer:

5.903 for radius

7 0
2 years ago
HELP ME NOW PLEASE, IM BEGGING.
svlad2 [7]
1. $1.23 per pair
A dozen is 12 so you do 12x7=84

Then you do 103.32 divided by 84 which gives you 1.23

2. His error was doing 103.32 divided by 7 because he thought it was only 7 pairs but it’s 7 dozen.
3 0
2 years ago
Read 2 more answers
Considere as seguintes afirmações: I. O inverso de 0,2 é 5. II. O triplo de \frac{2}{5} é \frac{6}{15}. III. A metade de 0,5 é \
Alex777 [14]

Answer:

I e III

Step-by-step explanation:

Recebemos declarações na questão acima para considerar.

Declaração I. O inverso de 0,2 é 5.

Matematicamente, isso é escrito como:

1 / 0,2

0,2 = 2/10

Portanto: 1 ÷ 2/10 = 1 × 10/2

= 5

Afirmação 1 é verdadeira

Declaração II.

O triplo de 2/5 é 6/15.

Triplo de 2/5 = 2/5 + 2/5 + 2/5

= 2 + 2 + 2/5

= 6/5

= 1 1/5

Declaração II é falsa

III. A metade de 0,5 é 1/5

1/2 de 0,5

= 1/2 × 0,5 = 0,25

Convertendo em fração

= 0,25 = 25/100

= 1/4

Declaração III está correta

Portanto, as afirmações verdadeiras são I e III

8 0
2 years ago
Trigonometry:
Trava [24]

A. The approximate height of the building is 100 m

B. We can use the arc length formula to obtain an approximation of BC since angle A is small.

A.

The approximate height of the building is 100 m

To find the approximate height of the building, we consider the diagram.

From the diagram, we have that using trigonometry,

tanA = BC/AB

Now

  • A = 0.05 radians,
  • BC = height of building and
  • AB = 2 km = 2000 m
<h3 /><h3>Finding the value of BC</h3>

So, making BC subject of the formua, we have

BC = ABtanA

Substituting the values of the variables into the equation, we have

BC = ABtanA

BC =2000tan0.05

BC = 2000 × 0.05

BC = 100 m

So, the approximate height of the building is 100 m

B.

We can use the arc length formula to obtain an approximation of BC since angle A is small.

<h3 /><h3>Arc Length Formula</h3>

We know that the arc length formula L = rФ where

  • r = radius and
  • Ф = angle in radians
<h3 /><h3>The approximate height</h3>

Now BC = ABtanA

We know that Ф ≅ tanФ when Ф is small.

<h3 /><h3>The comparison</h3>

So, BC = AB × A which is the arc length formula with

  • L = BC,
  • r = AB and
  • Ф = A

So, we can use the arc length formula to obtain an approximation of BC since angle A is small.

Learn more about approximate height of building here:

brainly.com/question/3144976

7 0
2 years ago
I need help please and thank you ( show your work please)
Bas_tet [7]

Answer:

y = 2x

Step-by-step explanation:

Use Rise over Run. The rise(up/down) is 2 and the run(sideways) is 1. The slope is going up, not down so the 2 is positive. So, it is positive 2/1, which you can write as 2.

7 0
1 year ago
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