Answer:
A) 0.2g
Step-by-step explanation:
Find the value of m for which mx^2 - 6x + 5 = 0 has one solution.
1 answer:
Answer:
m =
Step-by-step explanation:
Given a quadratic equation in standard form ax² + bx + c = 0 ( a ≠ 0)
Then the discriminant Δ = b² - 4ac gives information on the nature of the solutions.
For the equation to have 1 solution we require b² - 4ac = 0
mx² - 6x + 5 = 0 ← is in standard form
with a = m, b = - 6, c = 5, then
b² - 4ac = 0
(- 6)² - (4 × m × 5) = 0
36 - 20m = 0 ( subtract 36 from both sides )
- 20m = - 36 ( divide both sides by - 20 )
m = =
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Option C:
x = 90°
Solution:
Given equation:
<u>To find the degree:</u>
Subtract 1 + cos²x from both sides.
Using the trigonometric identity:
Let sin x = u
Factor the quadratic equation.
u + 2 = 0, u – 1 = 0
u = –2, u = 1
That is sin x = –2, sin x = 1
sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.
sin x = 1
The value of sin is 1 for 90°.
x = 90°.
Option C is the correct answer.