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exis [7]
3 years ago
14

Solve this inequality: 3b – 7 < 32

Mathematics
2 answers:
butalik [34]3 years ago
6 0
It's a lot like solving equations.

3b-7 < 32
Add 7 to each side.
3b < 39
Divide by 3 on each side.
b < 13

Hope this helps :)
makkiz [27]3 years ago
3 0

Answer:

D) b < 13 .

Step-by-step explanation:

Given  :  3b – 7 < 32 .

To find : Solve this inequality.

Solution : We have given 3b – 7 < 32 .

On adding 7 both sides both sides.

3b < 32 + 7.

3b < 39.

On dividing both sides by 3.

b < 13 .

Therefore, D) b < 13 .

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A gourmet pizza café sells three sizes of pizzas. If you buy all three sizes, it costs $46.24. A medium pizza costs $15.75 and a
avanturin [10]

Answer:

Step-by-step explanation:

You need to subtract the prices of the medium and large from the total

Small = 46.24 - medium -  large

17.50 + 15.75 = 33.75

S = 46.24 - 33.75

S = 12.99

8 0
3 years ago
An ancient Roman coin is found and a curious anthropologist wishes to determine if the coin is fair— Fair meaning that when flip
Mamont248 [21]
The coin wouldn't be fair, because it landed on heads 72/100 times. If the coin was fair, the results should be equivalent to 1/2.
7 0
3 years ago
Read 2 more answers
The password for a new online gaming site must contain three letters followed by four digits . The digits can be repeated by but
vesna_86 [32]

Answer:

If I am correct, then it is 1,867,866,560 .

Share

Step-by-step explanation:

7 0
2 years ago
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
Sandeep used 8 litres of fuel to travel 76 miles.
OleMash [197]

Answer:

I got, when calculated, 209 miles. (It may be wrong)

Step-by-step explanation:

First, I calculated how many miles can Sandeep travel with 1L, therefore I divided 76 miles by 8L and got 9.5 miles on 1L.

Then I multiplied 9.2 miles by 22L and got 209 miles.

This may be wrong but if anyone else is able to work it out much appreciated if it's correct.. Your most welcome!

4 0
2 years ago
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