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3 years ago

you roll a 6-sided die with faces numbered 1 through 6, and toss a coin what is the probability of rolling a 2 or getting heads

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

You have 6 possible outcomes. Getting 1 outcome is 1/6. You have 2 possible outcomes. Getting 1 outcome is 1/2.

Add 1/2 and 1/6 to get 2/3

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What’s the square route of 169

Mazyrski [523]

Answer:

± 13

Step-by-step explanation:

$\sqrt{169}$ = ± 13, since

13 × 13 = 169 and - 13 × - 13 = 169

3 0

3 years ago

Read 2 more answers

What is the sum of the measures of 1, 2, 3 and 4?

fiasKO [112]

Answer:

360°

Step-by-step explanation:

1+3=180°

2+4=180°

so, ( 1+3)+(2+4)=360°

or:

1+2=180°

3+4=180°

so, so,( 1+2)+(3+4)=360°

7 0

4 years ago

√8 x √2 = 10 - 3 x 4 1/2

MrMuchimi

Answer:

Exact Form:

2√2

Decimal Form:

2.82842712

i think

5 0

3 years ago

Read 2 more answers

Pls help. Can’t do this.

Anna [14]

Step-by-step explanation:

The equation of line A:

y-1=0, 5x-3

y=0, 5x-2. Hence its gradient is 0,5

For line B, its you intercept is -8, so y=mx-8.

When x = -4, y=-4m -8 =0 as shown in the graph. This means that m = -2.

Since |-2| > |0, 5|, line B is steeper than line A.

6 0

3 years ago

I want to take a survey of students at my university to find out what proportion like the new bus service on campus. I believe t

tatiyna

Answer:

You will need to sample at least 3108 students.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem, we have that:

$\pi = 0.75$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

How many students will I need to survey if I want to estimate, with 99% confidence, the true proportion to within 2%?

You need a sample size of at least n.

n is found when M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.575\sqrt{\frac{0.75*0.25}{n}}$

$0.02\sqrt{n} = 1.115$

$\sqrt{n} = \frac{1.115}{0.02}$

$\sqrt{n} = 55.75$

$\sqrt{n}^{2} = (55.75)^{2}$

$n = 3108$

You will need to sample at least 3108 students.

4 0

3 years ago