True
A genotype is the combination of genes in its DNA of the organism that determines its traits
Explanation:
Gametes from parents contribute different alleles of genes to their offspring. This why gametes carry only one copy of genetic material of the organism. They later fuse to form a zygote with a full genetic copy and capable of developing into an full organism.
Depending on which kind of alleles the parents pass down to the offspring will determine the offspring's genotype. The genotype of the offspring will, on the other hand, affect its phenotype which is the outward characteristic. An example is the sickle cell trait. If both gametes from the parents contribute the recessive alleles of the gene, then the offspring will be homozygous recessive for sickle cell genotype and this will show in the phenotype pf the person who will have sickle cell shaped blood cells.
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Answer:
When the water evaporates, it leaves behind a solid layer of minerals
What grade are you in if you are in 5th or 6th i can help you
Answer:
The life cycle of plants is composed of sporophye generation and gemetophyte generation. They show alternation of generation in which gametophytr produce gametes that develop into sporophytic plant. Sporophye produce spores that develop into gametophyte plants.
Example:
Bryophytes, pinus etc
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
