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Aleksandr [31]
3 years ago
8

claire was able to verify that x=3 was a solution to her teacher's linear equation, but the equation got erasted from thw board.

what might the equation have been? identify as many equations as you can with a solution of x=3.
Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
X+5=8
x+(-7)=-4
4+x=7
7-x=4
3-x=0
-9×x= -27
those are just a few options
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Rewrite the expression -8(2+9v) using the distributive property
Ann [662]

Answer:

-16-72v

Step-by-step explanation:

-8*2 = -16

-8*9v = -72v

so, -16 + (-72v) -> -16-72v

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3 years ago
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Evgen [1.6K]

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3.3 and 5

Step-by-step explanation:

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What is 14c12?<br> A. 78<br> B. 91<br> C. 105<br> D. 120
Delicious77 [7]

9514 1404 393

Answer:

  B.  91

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3 years ago
Tyler is 8 years old. His sister Olivia is 4 years less than twice his age. Write a numerical expression for Olivia's age in the
Marat540 [252]
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6 0
3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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