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ValentinkaMS [17]
2 years ago
12

Will give brainliest What goes on the blank? A ? B? C? D? E? F?

Mathematics
1 answer:
Gre4nikov [31]2 years ago
3 0
A will be 360/4
B will be pentagon
C will be 72
D will be hexagon
E will be 360/60
F will be 51.428571
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For a particular​ event, 771 tickets were sold for a total of ​$3037. If students paid ​$3 per ticket and non-students paid ​$5
BlackZzzverrR [31]

Answer:

Number of student tickets were sold = 409

Step-by-step explanation:

Total number of tickets sold = 771

I.e Students ticket (S) + Non students ticket(N S)  = 771

Total amount to be paid for tickets = $ 3037

Amount paid by students per tickets = $3

Amount paid by non-students per tickets = $5

So, according to question

S + NS = 771

3 S + 5 NS = 3037

Solve both equations  

5 S + 5 NS = 771 × 5

3 S + 5 NS = 3037

so ,

(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037

Or, 2 S = 818

I.e S = \frac{818}{2} = 409

Hence, The number of student tickets were sold = 409      Answer

5 0
2 years ago
I need help with solving this
leva [86]

Answer:

49

Step-by-step explanation:

Positive 49 not -49

3 0
3 years ago
How do you write the number 50,679 in word form and expanded form
GarryVolchara [31]
"fifty thousand six hundred and seventy nine" and 50,000 + 600 + 70 + 9
4 0
2 years ago
It takes 45 minutes for 4 people to paint 5 walls.
Molodets [167]

4 people x 45 minutes = 180 minutes total to paint 5 walls

180/5 = 36 minutes of man work per wall

36 * 4 walls = 144 total minutes

144/6 people = 24 minutes total


4 0
3 years ago
A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. How many different combinat
Stella [2.4K]

Answer:

8 different combinations are possible.

Step-by-step explanation:

Here, we have 2 different combinations for each time.

And the player comes out to bat 3 times.

So, total number of combinations are:

2^{3} i.e. a total of 8 number of times.

Let a hit is termed as 'H' and an out is termed as 'O'.

Total combinations are:

{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}

Kindly have a look at the tree diagram attached in the answer area.

In starting, there are 2 combinations possible, i.e. 'O' and 'H'.

After 'O' , 2 possible i.e. 'O' and 'H'.

After 'H' , 2 possible i.e. 'O' and 'H'.

and so on....

8 0
3 years ago
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