What z score in a normal distribution has 33% of all score above it?
Answer: A z score which has 33% of all scores above it, will have 67% of all scores below it.
To find the required z score, we need to find the z value corresponding to probability 0.67.
Using the standard normal table, we have:
Therefore, the z score = 0.44 has 33% of all score above it.
Answer:
0.8181818
Step-by-step explanation:
3/11×3 = 0.8181
<span>A+B)^2 is the largest. It is A^2+2AB+B^2, which is clearly greater than the last two options. To compare (A+B)^2 and 2(A+B), we remove one A+B so that we're just comparing A+B and 2. As A+B must be at least 3 (as both must be positive integers, and one must be greater than the other, leading to a minimum value of A=2, B=1), A+B is greater than 2, and as a result, (A+B)^2 is always the largest.</span>
72. Explanation: 36+72=108.
V = s^2(h/3)
is the formula....................<span />
