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Norma-Jean [14]
3 years ago
8

The value of a rare baseball card A appreciated by 20 percent over a five year period; over the next five years, the value plumm

eted by 50 percent. Over the same total time period, the value of another card B increased by 100%. At the end of ten years, the reduced value of A was what percent of the increased value of B?
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
<h2>Answer:</h2>

<em><u>Percent value of A with respect to Percent value of B is,</u></em>

30\%

<h2>Step-by-step explanation:</h2>

In the question,

Let us say the value of the Baseball card A and B initially is = 100x

So, for Baseball card A in first 5 years percent increase = 20%

So,

Value after 5 years = 100x + 20% of 100x = 120x

<u>After 5 more years,</u>

Percent decrease = 50%

So,

<u>Value at the end of 10 years = 120x - 50% of 120x = 60x</u>

Now,

For Baseball card B, Percent increase in 10 years = 100%

So,

<u>Value of card B = 100x + 100% of 100x = 200x</u>

So,

<em><u>Percent value of A with respect to Percent value of B is,</u></em>

\frac{60x}{200x}\times 100=30\%

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Answer:

A. (5,5)

Step-by-step explanation:

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pshichka [43]

____________________________________________________

Solve for x:

3(x - 5) = 6

Distribute the 3 to the variables inside the parenthesis

3x - 15 = 6

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7>x>1
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8 0
3 years ago
Carter invested $16,000 in an account paying an interest rate of 5.6% compounded monthly. Assuming no deposits or withdrawals ar
jenyasd209 [6]

Answer:

11 years.

Step-by-step explanation:

Given that Carter invested $ 16,000 in an account paying an interest rate of 5.6% compounded monthly, to determine, assuming no deposits or withdrawals are made, how long would it take, to the nearest year, for the value of the account to reach $ 29,600, the following calculation must be performed:

16,000 x (1 + 0.056 / 12) ^ Yx12 = 29,600

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16,000 x 1.4666 ^ 132 = X

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Thus, rounded to the nearest year, it would take 11 years for the account to reach $ 29,600.

8 0
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rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

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Total number of different tickets are possible is

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Therefore, 4032 different tickets are possible.

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