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Norma-Jean [14]
3 years ago
8

The value of a rare baseball card A appreciated by 20 percent over a five year period; over the next five years, the value plumm

eted by 50 percent. Over the same total time period, the value of another card B increased by 100%. At the end of ten years, the reduced value of A was what percent of the increased value of B?
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
<h2>Answer:</h2>

<em><u>Percent value of A with respect to Percent value of B is,</u></em>

30\%

<h2>Step-by-step explanation:</h2>

In the question,

Let us say the value of the Baseball card A and B initially is = 100x

So, for Baseball card A in first 5 years percent increase = 20%

So,

Value after 5 years = 100x + 20% of 100x = 120x

<u>After 5 more years,</u>

Percent decrease = 50%

So,

<u>Value at the end of 10 years = 120x - 50% of 120x = 60x</u>

Now,

For Baseball card B, Percent increase in 10 years = 100%

So,

<u>Value of card B = 100x + 100% of 100x = 200x</u>

So,

<em><u>Percent value of A with respect to Percent value of B is,</u></em>

\frac{60x}{200x}\times 100=30\%

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Cual es el resultado de la operacion algebraica: 25x+12x+31x-8x+5x
Tema [17]

Answer:

65x

Step-by-step explanation:

Observe que estos son terminos similares... por lo que podemos simplemente sumarlos y restarlos. Entonces obtenemos:

25x + 12x + 31x - 8x + 5x

= 37x + 31x - 8x + 5x

= 68x - 8x + 5x

= 60x + 5x

= 65x

7 0
3 years ago
Beakers X and Y contain some water. If 50 ml of water is transferred from Beaker X
eduard

Answer:

140 ml

Step-by-step explanation:

Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.

<u>Then we get following equations:</u>

<u>First part</u>

  • x - 50 = 3/7(y + 50)
  • 7x -350 = 3y + 150
  • 7x = 3y + 500

<u>Second part</u>

  • x + 100 = 4(y - 100)
  • x + 100 = 4y - 400
  • x = 4y - 500

<u>Substitute x in first equation:</u>

  • 7(4y - 500) = 3y + 500
  • 28y - 3500 = 3y + 500
  • 28y - 3y = 500 + 3500
  • 25y = 4000
  • y = 4000/25
  • y = 160 ml

<u>Then finding x:</u>

  • x = 4*160 - 500
  • x = 640 - 500
  • x = 140 ml

Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml

4 0
3 years ago
The original price of a video game is $45. What is the sale price after a 25% discount.​
Ghella [55]

Answer:

33.75

Step-by-step explanation:

5 0
3 years ago
What is the solution to the system of equations below?
disa [49]

The solution to the system of equation are x=2, y=0, z=6

<h3>System of equations</h3>

System of equations are equations that contains unknown variables.


Given the equations

3x+y+2z=8

8y+6z=36

12y+2z=12

From equation 2 and 3

8y+6z=36 * 1

12y+2z=12 * 3

______________

8y+6z=36

36y+6z= 36

Subtract

8y - 36y = 36 - 36

-28y =0

y = 0

Substitute y = 0 into equation 2

8(0)+6z=36

6z = 36

z = 6

From equation 1

3x+y+2z =8

3x + 0 + 2(6) = 8

3x = 8 - 12

3x = 6

x = 2

Hence the solution to the system of equation are x=2, y=0, z=6

Learn more on system of equation here: brainly.com/question/14323743

#SPJ1

3 0
1 year ago
Identify the constant of<br> proportionality (k)<br> 8Y = 16x<br> k=
RUDIKE [14]

Answer:

JUST WRITE THIS AS YOUR ANSWER

Step-by-step explanation:

Step 1: Put together the general equation.

Step 2: Solve for the constant of proportionality.

Step 3: Plugging the constant into the equation, solve for the unknown variable.

Let's solve a few problems to see how this works, shall we?

Example 1: Y is directly proportional to x. When x = 5, y = 8. What does y equal when x = 9?

First, we set up our general equation. Because y is directly proportional to x, we have:

y = cx

where c is the constant of proportionality. In other words, when x goes up, y goes up, and when x goes down, y goes down.

The next thing we do is plug our values for x and y into the equation so we can solve for c:

8 = (c)(5)

Solving for c, we get c = 8/5 = 1.6 and we plug this into our equation:

y = 1.6x

Now, we can plug x = 9 into the equation to find out what y equals:

y = (1.6)(9)

y = 14.4

So, our answer is 14.4

Example 2: Y is directly proportional to the square of x. When x = 2, y = 32. What does y equal when x = 5?

This time, our general equation is slightly more complicated because x is squared:

y = cx2

Like before, we solve for our constant:

32 = (c)(22)

32 = (c)(4)

We get c = 8:

y = 8x2

Solving for y when x = 5, we get y = (8)(52) = (8)(25) = 200

Example 3: Y is inversely proportional to x. When x = 2, y = 8. What does y equal when x = 24?

This time, because y is inversely proportional to x, our general equation is different:

xy = c

so when x goes up, y goes down, and vise versa. But, other than that, we solve these kinds of problems the same way as direct proportion problems. Solving for the constant, we get:

(2)(8) = c

So c = 16 and our equation is now:

xy = 16

Solving for y when x = 24 we get y = 16/24 = 2/3

Example 4: Y is inversely proportional to the square root of x. When x = 36, y = 2. What does y equal when x = 64?

As before, we set up our equation:

eq001

Since the square root of 36 is 6, it is easy to solve for c:

(6)(2) = c

We get c = 12 and our equation is now:

eq002

Solving for y when x = 64 we get 8y = 12 or y = 12/8 = 1.5 because the square root of 64 is 8.

6 0
3 years ago
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