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3 years ago

8

The area of the bottom of a circular pool 452.2 ft2. What is its circumference, rounded to the nearest tenth?

1 answer:

Alborosie3 years ago

8 0

The area of a circle is given by A=Pi*r^2, and its perimeter, P=2*Pi*r.

To get the radius r, you must divide 452.2 by Pi, and then calculate the square root of this quotient.

To get the circumference or perimeter, use the radius in the formula P=2*Pi*r.

Finally, round the number you get to the nearest tenth.

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In right ∆LMN, sin M = 0.759. What is cos N? A. 0.121 B. 0.241 C. 0.349 D. 0.651 E. 0.759

Hatshy [7]

Answer:

E. 0.759

Step-by-step explanation:

You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN

The sine of angle ∠LMN is 0.759, find the value of ∠LMN

$sin^-1(0.759)=49.38$

∠LMN=49.38°

Find angle ∠LNM

You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence

∠LNM=180°-(90°+49.38°)

∠LNM= 180°-139.38°=40.62°

Find cos 40.62°

Cos 40.62°=0.7590

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A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

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