All categories

3 years ago

Given m||n, find the value of x. (explain answer if u can) ASAP!!

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

7 0

Answer:

Step-by-step explanation: I think it's 7 according to my calculations

Marizza181 [45]3 years ago

3 0

Easy. Do (3x + 10) + (6x -10) = 180. You add them up since they are same side interior angles. This gives you 9x = 180
Divide by 9 on both sides. x = 20. Hope this helps!

You might be interested in

(2/3) / (-1/2)<br> How do I divide these 2 fractions?

dsp73

Answer:

Step-by-step explanation:

2/3*(-2/1)

$-\frac{4}3}$

Hope it helps! Please mark Brainliest if it does!

4 0

3 years ago

Read 2 more answers

A substance weighing 961 ounces decays at a rate of 3.2% PER HOUR. What is the weight of the substance after ONE DAY?

kifflom [539]

It would be 961 x (1-3.2(24)) and that would be 961(.232)= 222.952

6 0

3 years ago

Read 2 more answers

How do you get angle x using trigonometry in a right angled triangle?

Scorpion4ik [409]

Answer:

Example

Step 1 The two sides we know are Adjacent (6,750) and Hypotenuse (8,100).

Step 2 SOHCAHTOA tells us we must use Cosine.

Step 3 Calculate Adjacent / Hypotenuse = 6,750/8,100 = 0.8333.

Step 4 Find the angle from your calculator using cos-1 of 0.8333:

3 0

3 years ago

Please help, im having trouble cancelling out the numbers and letters! :) thank you

stiv31 [10]

First change the devision to multiplication
second see the common letters and cross them

8 0

3 years ago

x axis is x = 4.00 - 7.00t2, with x in meters and t in seconds. (a) At what time and (b) where does the particle (momentarily) s

andrezito [222]

Answer:

(a) 0 s

(b) 4.00 m

(d) +0.76 s

Step-by-step explanation:

$x=4.00-7.00t^2$

It stops momentarily when the velocity, $v$ is 0. $v$ is the derivate of $x$ .

(a) $v=\frac{dx}{dt}=-14.00t$

Setting this to 0,

$-14.00t=0$

$t=0$

(b) Substitute this value for $t$ in $x$ to get its position.

$x=4.00-7.00\times0^2=4.00$ m

It passes the origin when $x=0$

$4.00-7.00t^2=0$

$7.00t^2=4$

$t^2=\frac{4}{7}$

$t=\pm\sqrt{\frac{4}{7}}$

(d) The positive time is $t=+\sqrt{\frac{4}{7}} =+0.76 s$

8 0

4 years ago