Point - slope form = y - y1 = m(x - x1)
y - 4 = 2(x-1)
Answer:
ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.
That is, S = D/t
Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have
S1 = D1/t
We can then say he ran a distance
D1 = t × S1
= 3600S1
Similarly, let's say Karleigh ran a distance
D2 = t × S2
= 3600S2
Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.
Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10
D1 = 3600 × 5
= 18000
D2 = 3600 × 10
= 36000
This makes D2 bigger than D1. this is an example i found on the internet.
Step-by-
hope this helps, good luck
Answer:
a. segment DE and segment EF are congruent to each other but not to segment DF, and their slopes are not related.
Step-by-step explanation:
In order for a triangle to be isosceles, two of the line segments must be congruent. (eliminates choices C and D)
If the slopes of the congruent segments are negative reciprocals of each other, the triangle is a right triangle, not an acute triangle. (eliminates choice B)
With choices B, C, D eliminated, we are left with choice A.
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However, <em>that necessary description is not sufficient</em> to constrain the triangle to be an acute triangle. In order for the triangle to be acute, the third side must be less than √2 times the length of either of the congruent sides.
The correct answer is "none of the above."
Answer:
Option D. 5890.5 feet²
Step-by-step explanation:
An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.
Yard has three sprinkler heads that each cover circular area with no overlap.
We have to calculate the approximate area watered by these 3 sprinkler heads.
Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²
Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²
which matches the approximate value of Option D. 5890.5 feet²
