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liq [111]
3 years ago
13

The formula for the perimeter of a rectangle is P=2(L+W) solve for W.

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0
Cccccccccccccccc because u would want to get w by it self
nirvana33 [79]3 years ago
6 0

Answer:

Option A - W=\frac{P}{2}-L

Step-by-step explanation:

Given : The formula for the perimeter of a rectangle is P=2(L+W).

To find : Solve for W ?

Solution :

The formula for the perimeter of a rectangle is

P=2(L+W)

Multiply,

P=2L+2W

Subtract 2L both side,

P-2L=2W

Divide by 2 both side,

W=\frac{P-2L}{2}

or W=\frac{P}{2}-L

Therefore, Option A is correct.

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F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
SVEN [57.7K]

Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

Function is F(t)=t^2+19+60

Zeroes of the function are

t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

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3 years ago
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Step-by-step explanation:

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First, find n:

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Now, find the sum of these 2k+1 terms:

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