Question

Celebration is being held honoring five award winners of different ages each winner will be called one at a time in random order what is the probability that the winners will be called in order by the age from youngest to oldest?

Answer 1

Answer:

1 in 120 or 0.83%

Step-by-step explanation:

There are 5 possible winners to be called first, 4 possible winners are then left to be called second, 3 to be called third, 2 to be called fourth and the final winner is left to be called last. Therefore, the number of possible ways to arrange the winners is:

$n=5*4*3*2*1\\n=120$

There is only one possible order for which the winners are called in order by the age from youngest to oldest. Therefore, the probability of this happening is 1 in 120 or 0.83%.