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vlabodo [156]
4 years ago
15

A 200 mL K2SO4 solution with a concentration of 0.40 M is mixed with 400 mL of a K2SO4 solution containing 7% K2SO4 (m/v). The m

olar mass of K2SO4 is 174.3 g/mol. What is the final concentration of K2SO4 in the solution in molarity
Chemistry
1 answer:
Olegator [25]4 years ago
7 0

Answer:

The final concentration in molarity (M) is 0.4

Explanation:

K₂SO₄ (Potassium sulfate) - Molar mass = 174.3 g/m

First of all, we have 200 mL, 0.4 M

Molarity . volume = mol

(mol/L) . L = mol → 0.4 mol/L . 0.2L = 0.08 moles of salt, in the beginning.

In second situation we have 7% m/v of salt, which means that in 100 mL of solution, we have 7 grams of solute.

7 g / 174.3 g/m = 0.040 moles in 100 mL

Let's think the rule of three:

In 100 mL we have 0.04 moles of salt

in 400 mL we have (400 . 0.04)/100 = 0.16 moles

1st situation: 0.08 moles of salt

2nd situation: 0.16 moles of salt

Total moles = 0.08 + 0.16 = 0.24 moles

Total volume = 200 mL + 400 mL = 600 mL

Molarity = mol/L

0.24 mol / 0.6L = 0.4M

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Define law of conservation of mass
horrorfan [7]

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction. Hope this helps!


7 0
4 years ago
An aqueous solution of ________ will produce a neutral solution. An aqueous solution of ________ will produce a neutral solution
IRINA_888 [86]

Answer:

An aqueous solution of  NaF will produce a neutral solution.

Explanation:

In order to classify the solutions, we need to dissociate all the salts and determine the conjugate pairs of base and acids.

NaNO₂ → Na⁺  + NO₂⁻

Na⁺ comes from the NaOH, a strong base, so the Na⁺ is the conjugate weak acid from the strong base. It will not react. This is a basic salt.

The NO₂⁻  is a conjugate strong base, that comes from the weak acid, nitrous acid. This ion can make hydrolisis.

NO₂⁻  +  H₂O  ⇄    HNO₂   +  OH⁻          Kb

We give OH⁻ to medium, so solution is basic.

Li₂CO₃  →  2Li⁺  +  CO₃⁻²

Li⁺ comes from the LiOH, a strong base, so the cathion is the conjugate weak acid from the strong base. It will not react

The CO₃⁻²  is a conjugate strong base, that comes from the weak acid, carbonic acid. This ion can make hydrolisis.

CO₃⁻²  +  H₂O  ⇄    HCO₃⁻  +  OH⁻      Kb

NaClO₄ →  Na⁺  +  ClO₄⁻

Na⁺ comes from the NaOH, a strong base, so the cathion is the conjugate weak acid from the strong base. It will not react

The ClO₄⁻  is a conjugate strong base, that comes from the weak acid, perchloric acid. This ion can make hydrolisis. This is a basic salt.

ClO₄⁻  +  H₂O  ⇄    HClO₄⁻  +  OH⁻      Kb

NH₄ClO₄  →  NH₄⁺  +  ClO₄⁻

Both ions can make hydrolisis. Ammonium comes from a weak base, so it is the strong conjugate base, and  ClO₄⁻  is a conjugate strong base, that comes from the weak acid, perchloric acid

NH₄⁺  +  H₂O  ⇄  NH₃  +  H₃O⁺         Ka

ClO₄⁻  +  H₂O  ⇄    HClO₄⁻  +  OH⁻      Kb

This sort of salt are generally acid.

NaF  →  Na⁺  + F⁻

As we have seen, Na⁺ comes from the NaOH (a strong base) so it will not react.

This equilibrium can not occur: Na⁺  + H₂O ←  NaOH   +  H⁺

F⁻  comes from a strong acid, HF so it will not also react. This reaction can not occur too: F⁻  + H₂O ←  HF   +  OH⁻

We do not have reaction in this neutral salt, so the pH is neutral.

8 0
3 years ago
Carbon atoms can bond together in straight chains branched chains or rings. true or false
FrozenT [24]

Answer:

The answer to your question is: True

Explanation:

Carbon compounds

Aliphatic       saturated         only have single bonds

                     unsaturated    could have double or triple bonds

Ciclic            are skeletons of carbons that forms cycles

Aromatic      the unit of this compounds is benzene, which is a cycle of

                    6 carbons.

7 0
4 years ago
Predict the Solubility of the following substances in water.
anyanavicka [17]
<span>a. NaNO3: soluble
b. AgBr: insoluble
c. NH4OH: soluble
d. Ag2CO3: insoluble
e. NH4Br: soluble
f. BaSO4: insoluble
g. Pb(OH)2: soluble
h. PbCO3: insoluble</span>
5 0
3 years ago
Give four method of acid preparation and give two reactions to support your answers
gregori [183]

(i) Hydrogen chloride gas is prepared by treating Sodium chloride with concentrated sulphuric acid. The HCl gas is passed through a drying agent to remove moisture where concentrated sulphuric acid plays the role of dehydrating agent as well.

(ii) NaCl+H2 SO4  →NaHSO 4 +HCl(g)

Hope it helps :)

5 0
3 years ago
Read 2 more answers
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