What is the ratio of Fe3+ ions to O2- ions in a neutral compound? 1:2 2:1 2:3 3:2,
1 answer:
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Answer:
14.4 g of can be produced.
Explanation:
Balanced equation:
Molar mass (g/mol)
58.12
32
44.01
So, 9.60 g of =
17.0 g of =
According to balanced equation-
2 moles of produce 8 moles of
So, 0.165 moles of produce
of
or 0.660 moles of
13 moles of produce 8 moles of
So, 0.531 moles of produce
of
or 0.327 moles of
As least number of moles of are produced from
therefore
is the limiting reagent.
So, maximum amount of that can be formed = 0.327 moles
=
= 14.4 g
Answer:
≈170.22 [gr].
Explanation:
1) M(Cu₂CO₃)=2*64+12+3*16=188 [gr/mol];
2) the part of copper in Cu₂CO₃ is:
3) 16/47% of 500 [gr] is: