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Vlada [557]
3 years ago
6

Ok last question for today Will mark brainliest

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:9


Step-by-step explanation:

8 * 9 = 72

8, 16, 24, 32, 40, 48, 56, 64, 72

1, 2, 3, 4, 5, 6, 7, 8, 9

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What should be multiplied by the expression in the image to obtain the smallest square
makkiz [27]

Answer:

2xy

Step-by-step explanation:

Here, we want to obtain the number with the smallest square

To get this, we simply find the nearest number square which is 2

The nearest x squared which is x (to get x^4)

The nearest y squared which is y (to get y^2)

Thus, the smallest number so we get a square will be; 2xy

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2 years ago
What mixed number represents the length of the phone screen
Anni [7]
That depends on the length of the phone

4 0
3 years ago
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The proper height of a highway guardrail is 27 inches, but 3 inches higher or lower is acceptable. Which inequality represents t
andriy [413]

Answer:

Step-by-step explanation:

27 is the "center" of a range of measurements of the height of the guard rail.  The height could be as much as 30 inches or as little as 24 inches.  The absolute value operator encloses "x - 27," where 27 is the "center."  The acceptable excess or acceptable deficiency is 3 inches.  

So now we can eliminate possible answers B and C, in both cases because 27 is inappropriately greater than 3.

Narrowing down our choices, we have h + 27 and h - 27 inside the absolute value operator.  27 is a positive quantity (height of the guard rail), so the inequality showing +27 as the "center" is correct; that is

D:  |h - 27| ≤ 3 (measurements in inches).

3 0
3 years ago
403, 395,387,...<br><br> Find the 36th term.
MArishka [77]

Answer:

n=36

a=403

d=395-403=8

an=a+(n-1)d

a36=403+(36-1)395

=14228

8 0
3 years ago
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B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
2 years ago
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