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seraphim [82]
3 years ago
11

What numbers are irrational. Square root of 45, square root of 64, square root of 21 , and square root of 21

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0
The square of 45 and square root of 21 are irrational. The square root of 64 is rational
liberstina [14]3 years ago
5 0

Answer: is A, C, D

A. √45= 6.7082039324993690892275210061938

B. √64= 8

C. √21= 4.582575694955840006588047193728

D. √21= 4.582575694955840006588047193728

Step-by-step explanation:

An Irrational Number is a real number that cannot be written as a simple fraction.

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How far is the little guy from the flagpole (assuming a right angle between the flagpole and the ground)? Explain how you got yo
Anvisha [2.4K]

Answer:

9

Step-by-step explanation:

a^2 + b^2 = h^2

15^2= 12^2 + b^2

225=144+b^2

81=b^2

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7 0
3 years ago
Suppose that Fx) = x3 and G(x) = -2x2. Which statement best compares the
Rudiy27

Answer:

D

Step-by-step explanation:

you can just find the value of y and try some number of x

i.e. if x = 0, both of them will be 0

x = 1

G(x) result is -2

F(x) result is 1

x= -1

G(x) result will be 2

F(x) result is -1

so from these we can prove that G(x) is bigger graph than F(x) but flip vertically by y axis

8 0
3 years ago
I do t know how to do it
Luba_88 [7]

We know: the sum of the angles measures in a triangle is 180°.

Therefore we have the equation:

64° + 75° + α = 180°

139° + α = 180°      <em> subtract 139° from both sides</em>

α = 41°

α and ∠2 are Supplementary Angles - they add up to 180°.

α + m∠2 = 180°

41° + m∠2 = 180°    <em>subtract 41° from both sides</em>

<h3>m∠2 = 139°</h3>

7 0
3 years ago
Which expression represents this word phrase? seven less than the quotient of x and 9
KIM [24]
Required expression is x/9 - 7
4 0
3 years ago
Middle School: Math (10 Points)
sasho [114]
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:

A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?

You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked

2) a - 2%  as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.  

b - 1,000,000/2500 = 400
400 packages are defective each year
5 0
3 years ago
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