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seraphim [82]
3 years ago
11

What numbers are irrational. Square root of 45, square root of 64, square root of 21 , and square root of 21

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0
The square of 45 and square root of 21 are irrational. The square root of 64 is rational
liberstina [14]3 years ago
5 0

Answer: is A, C, D

A. √45= 6.7082039324993690892275210061938

B. √64= 8

C. √21= 4.582575694955840006588047193728

D. √21= 4.582575694955840006588047193728

Step-by-step explanation:

An Irrational Number is a real number that cannot be written as a simple fraction.

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Step-by-step explanation:

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You and your friend leave your houses at the same time to meet at a restaurant. The distance (in miles) your friend is from the
Katen [24]

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y = 80 -40x

Step-by-step explanation:

The given equation shows the friend arrives at the restaurant (y=0) when x=2. That is, half the initial distance to the restaurant is covered in each hour of travel time.

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Read 2 more answers
Suppose you have a sample of 27 Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups,
olchik [2.2K]

Answer:

Test statistic t=1.2531.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters (P-value=0.11).

Step-by-step explanation:

<em>The question is incomplete: We need the gestation length of the population to perform the hypothesis test. We assume it to be 16 days (μ=16).</em>

This is a hypothesis test for the population mean.

The claim is that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters.

Then, the null and alternative hypothesis are:

H_0: \mu=16\\\\H_a:\mu> 16

The significance level is 0.05.

The sample has a size n=27.

The sample mean is M=17.4.

The sample variance is s^2=33.7 days^2.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=33.7^(0.5)=5.81.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.81}{\sqrt{27}}=1.1172

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{17.4-16}{1.1172}=\dfrac{1.4}{1.1172}=1.2531

The degrees of freedom for this sample size are:

df=n-1=27-1=26

This test is a right-tailed test, with 26 degrees of freedom and t=1.2531, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.2531)=0.11

As the P-value (0.11) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that Syrian hamsters who were exposed to high levels of the hormone progesterone when they were pups have a different gestation length than all Syrian hamsters.

4 0
3 years ago
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