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irinina [24]
3 years ago
14

A rectangle has a width of 49cm and a perimeter of 218cm. What is the rectangle’s length?

Mathematics
1 answer:
Semmy [17]3 years ago
5 0

218 - 49 - 49 = 2l

128 = 2l

128/2 = 2l/2

64 = l

THe length is 64 because of teh algebraic method, l is the length, 49 is the width (2 of them) and 218 is the perimeter.

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The perimeter of a playing field for a certain sport is 254 ft. The length is 47 ft longer than the width. Find the dimensions.
Vikentia [17]

Answer: the length is 87 feet

The width is 40 feet

Step-by-step explanation:

Let L represent the length of the playing field.

Let W represent the width of the playing field.

The playing field is rectangular. The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of a playing field for a certain sport is 254 ft. This means that

254 = 2(L + W)

L + W = 254/2

L + W = 127 - - - - - - - - - - - -1

The length is 47 ft longer than the width. This means that

L = W + 47

Substituting L = W + 47 into equation 1, it becomes

W + 47 + W = 127

2W + 47 = 127

2W = 127 - 47 = 80

W = 80/2 = 40

L = W + 47 = 40 + 47

L = 87

4 0
3 years ago
What is the sum of y and 42 is at least 150
prohojiy [21]

Answer:

y + 42 \geqslant 150 \\ y \geqslant 150 - 42 \\ y \geqslant 108

7 0
3 years ago
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A school's math and science clubs are selling laundry soap bars to raise money to buy new calculators. The profit for each sold
Stolb23 [73]

i think it would be $16.24

3 0
3 years ago
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If a yard of fabric cost $12.99 then how much will 2 feet cost
Ratling [72]
We know that 1 ft= 1/3 yd.

2 ft* (1/3 yd/ 1 ft)* ($12.99/ 1 yd)= $8.66
(Note that the units cancel out so you get the answer)

2 ft of fabric will cost $8.66~
5 0
3 years ago
A rectangle is placed around a semi circle as shown below. The width of the rectangle is 7yd. find the area of the shaded region
Nady [450]

Answer:

21.07 yd^2

Step-by-step explanation:

The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.

The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.

area of shaded region = area of rectangle - area of semicircle

A = LW - (1/2)(pi)r^2

A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2

A = 98 yd^2 - (1.57)(49 yd^2)

A = 98 yd^2 - 76.93 yd^2

A = 21.07 yd^2

4 0
3 years ago
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