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sdas [7]
3 years ago
11

Find the quotient.

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0
See attached files for detailed solutions
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morpeh [17]
The answer is 4.5 × 10 -8
4 0
3 years ago
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In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flower
lutik1710 [3]

<u>Question Completion</u>

(a)What is your null hypothesis?

(b)What is your expected phenotypic ratio based on Mendelian inheritance?

(c)Calculate the expected number of flowers you should have gotten based on the Mendelian inheritance. Then calculate a chi-square value, degrees of freedom, and a p-value.

  • Chi-square statistic: _____
  • Degrees of freedom (# phenotypes -1):
  • P-value:

(d)Interpret your results. Do you reject it or fail to reject your null hypothesis (please restate the null)?

Answer:

(a)H_0:$The given data fit the predicted phenotype

(b)9:3:3:1

(c)

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1) =3
  • P-value:  0.2734

(d)We fail to reject the null hypothesis.

Step-by-step explanation:

In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flowers (e). An F2 generation was created by crossing two F1 individuals (each BbEe).

(a)The null hypothesis is:

H_0:$The given data fit the predicted phenotype

(b)The gametes are BE, Be, bE and be.

The offsprings are presented in the table below:

\left|\begin{array}{c|cccc}&BE&Be&bE&be\\--&--&--&--&--\\BE&BE&BE&BE&BE\\Be&BE&Be&BE&Be\\bE&BE&BE&bE&bE\\be&BE&Be&bE&be\end{array}\right|

The expected phenotypic ratio based on Mendelian inheritance

BE:Be:bE:be=9:3:3:1

(c)

\left|\begin{array}{c|c|c|c|c|c}$Phenotype&Observed&$Expected&O-E&(O-E)^2&\dfrac{(O-E)^2}{E} \\-----&--&--&--&--&--\\$White short(BE)&206&\frac{9}{16}*404 \approx 227 &-21&441&1.9427\\$Red, short(bE)&83&\frac{3}{16}*404 \approx 78 &5&25&0.3205\\$White, tall(Be)&85&\frac{3}{16}*404 \approx 78 &7&49&0.6282\\$Red, tall(be)&30&\frac{1}{16}*404 \approx 25 &5&25&1\\-----&--&--&--&--&--\\$Total&404&--&--&--&3.8914\end{array}\right|

Therefore:

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1):  4-1 =3
  • P-value:  0.2734

(d) Our null hypothesis is:

H_0:$The given data fit the predicted phenotype

Since p>0.05, the given data fit the predicted phenotypic ratio.

We, therefore, fail to reject the null hypothesis.

The difference in the observed and expected are sosmall that they can be attributed to random chance.

8 0
3 years ago
Tommy waves 45 kg Jamil Woods 53 kg what is the combined weight of the two boys in grams?
Nikolay [14]

Answer:

109,000

Step-by-step explanation:

1kg = 1000g

45 + 63 = 109

109 x 1000 = 109000

5 0
2 years ago
Kevin is twice as old as Sean. Together their ages add up to 75.
marissa [1.9K]

Answer:

Kevin would be 50 and Sean would be 25

Step-by-step explanation:

Assuming that there is no other information given,

and Kevin is twice as old as sean, and they gotta add up to 75 total

50 + 25 = 75

25x2 = 50

Hope this helped!

8 0
3 years ago
Read 2 more answers
Please help Im so confused!
mars1129 [50]

His mistake was adding 12+2 when he was supposed to subtract.

8 0
2 years ago
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