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Jlenok [28]
3 years ago
12

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Tatiana [17]3 years ago
6 0
First you are going to look at the smallest box and figure out what the area is once you do that you will need to find the area of the bigger box once you figure out both of the areas you will then find out what they are you will then add up the amounts to get the area of both squares together  

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Gala2k [10]
Do you have a question so I ca help?
5 0
3 years ago
If the area of a circle measures 25 pi cm², what is the circumference of the circle in terms of pi?
jeyben [28]

Answer:

10π cm

Step-by-step explanation:

Given

Area of the circle=25π cm^2

Solution

πr^2=25π

r^2=25

r=√25

r=5

So circumference of the circle=2πr

=2π×5

=10π cm

So the answer is 10π cm

8 0
2 years ago
I will give brainiest to whoever answers correctly !!
evablogger [386]

Answer:

markup=62 %

Step-by-step explanation:  

4 0
3 years ago
Read 2 more answers
On each of the 22 work days in a particular month, every employee of a start-up venture was sent a company communication. If a t
fiasKO [112]

Answer:

211

Step-by-step explanation:

As the statement indicates that on each of the 22 work days of the month the employees of the company received a communication and 4642 communications were sent, to be able to determine the number of employees that the company have, you have to divide the number of communications by the number of days:

4642/22= 211

The company has 211 employees.

3 0
3 years ago
Determine how many zeros, how many real or complex, and find the roots for f(x) = x3 − 5x2 − 25x + 125.
miskamm [114]
We can write this as:-

P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of  signs there are either 2  positive real roots or 0 positive roots.

P(-x)  = - x^3 - 5x^2 + 25x + 125 
There is just one change of sign  so  there is exactly 1 real negative root.

125 is a multiple of 5 so By rational root theorem  5 could be  a positive root.

P(5) =  125 - 125 - 125 + 125  = 0   so one zero is  5
if we divide   the polynomial by (x - 5) we get the quadratic
x^2 - 25 
(x + 5)(x - 5) = 0

x = 5,-5

so the roots are 5 (multiplicity 2)  and -5.
2 real positive zeroes  and one real negative zero
7 0
2 years ago
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