We know that<span>
<span>Figures can be proven similar if one, or more,
similarity transformations (reflections, translations, rotations, dilations)
can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a
translation and a scale factor (from a dilation) will be found to map one
circle onto another.
we have that</span>
<span> Circle 1 is centered at (5,8) and has a
radius of 8 centimeters
Circle 2 is centered at (1,-2) and has a radius of 4 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the
center of the circle 2
the transformation has the following rule</span>
(x,y)--------> (x-4,y-10)
so
(5,8)------> (5-4,8-10)-----> (1,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the
same center)
</span>
step 2
<span>A dilation is needed to decrease the size of
circle 1 to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle
1-----> 4/8----> 0.5
radius circle 1 will be=8*scale factor-----> 8*0.5-----> 4 cm
radius circle 1 is now equal
to radius circle 2
<span>A
translation, followed by a dilation will map one circle onto the other,
thus proving that the circles are similar
the answer is
</span></span>The circles are similar because you can translate Circle 1 using the transformation rule (x-4,y-10) and then dilate it using a scale factor of (0.5)
Compare it to 1/2 (which is the same as 6/12)
Answer:
A. Rotation 90º clockwise about the origin B. Rotation 180º about the origin C. Rotation 90º counterclockwise about the origin D. Reflection across y=x
Step-by-step explanation:
because
<span>so quarters to nickels would be 4:20. simplified is 1:5</span>
Answer:
0xFEE₁₆ = 7756₈
Step-by-step explanation:
Convert the hexadecimal number to decimal first
0xFEE
E = 14
F = 15
Then convert them to binary
Remainder = 0
Remainder = 1
Quotient = 1
Remainder = 1
Remainder = 1
Remainder = 1
Quotient = 1
Remainder = 1
0 F E E
0000 1111 1110 1110
Take groups of three
and multiply with 
where n is the place of the digit
111 111 101 110
4,2,1 4,2,1 4,2,1 4,2,1
4+2+1 4+2+1 4+0+1 4+2+0
7756
So, 0xFEE₁₆ = 7756₈
