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Elza [17]
3 years ago
10

100 POINTS!!! The table shows the values of a function f (x), What is the average rate of change of f (x) over the interval from

x = 5 to x = 9? Show your work.

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer:

1. (f(x)-f(a))/(x-a) **A(x)=(f(x)-f(a))/(x-a) This average rate of shift attribute is designated by the letter A. *f(x) - f(a) represents the difference in the function f as the input transitions from a to x. x - a represents the change in the input of the function f.

f(5)=-2 f(9)=14 (f(5)-f(9))/(5-9)=(-2-14)/-4=4 (f(5)-f(9))/(5-9)=(-2-14)/-4=4

Over the range of x = 5 to x = 9, the average rate of change is 4.

2. g(x)=2x2+13x+1, f(x)=4x2+6x

(f/g)(x)=(4x2+6x)/(2x2+13x+1) (f/g)(x)=(4x2+6x) (f/g)(x)=(4x2+6x)

f(x): 88/85,155/116,180/151,238/190,304/233,378/280 f(x): 88/85,155/116,180/151,238/190,304/233,378/280 f(x): 88/85,155/116,180/151,238/190,304/233,378/280 f(x): 88/85

3. f(x)=x2-6x+8, g(x)=x-2, g(x)=x-2, f(x)=g (x)

x2-6x+8=x-2, x2-6x-x+8+2=0, x2-7x+10=0, x2-6x-x+8+2=0

x1,2=(7+(72-4*10))/2=(7+3)/2 x1=5, x2=2 x1=5 x2=2

Step-by-step explanation:

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Factor 125x9 64. (5x3 – 4)(25x6 20x3 16) (5x3 – 4)(25x3 20x3 16) (5x3 4)(25x6 – 20x3 16) (5x3 4)(25x3 – 20x3 16).
MatroZZZ [7]

The factorization of \rm 125x^9 + 64 is  \rm (5x^3 + 4)(25x^6 - 20x^3 +16).

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; \rm 125x^9 + 64

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

\rm= 125x^9 + 64\\\\= 125x^9 -100x^6+80x^3+100x^6-80x^3+64 \\\\ =5x^3(25x^6 - 20x^3 +16) +4(25x^6 - 20x^3 +16) \\\\=(5x^3 + 4)(25x^6 - 20x^3 +16)

Hence, the factorization of \rm 125x^9 + 64 is  \rm (5x^3 + 4)(25x^6 - 20x^3 +16).

To know more about factorization click the link given below.

brainly.com/question/17595467

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