<span><span>╔╦╦╦╦╦╦ ╗</span><span>
<span>╠╬╬╬╬╬╬ ╣</span>
<span>╠╬╬╬╬╬╬ ╣</span>
<span>╠╬╬╬╬╬╬ ╣</span>
<span>╠╬╬╬╬╬╬ ╣</span>
╠╬╬╬╬╬╬╬╬╬╬╬╬╣
╠╬╬╬╬╬╬╬╬╬╬╬╬╣
╠╬╬╬╬╬╬╬╬╬╬╬╬╣
╠╬╬╬╬╬╬╬╬╬╬╬╬╣
<span>╚╩╩╩╩╩╩╩╩╩╩╩╩╝
Example - this is </span></span></span>
Answer:
yes its b
Step-by-step explanation:
The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=
(-4)=-8/(![-4)^{2}](https://tex.z-dn.net/?f=-4%29%5E%7B2%7D)
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+![f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............](https://tex.z-dn.net/?f=f%5E%7B1%7D%28-4%29%28x%2B4%29%2F1%21%2B%20%20f%5E%7B11%7D%28-4%29%28x%2B4%29%5E%7B2%7D%2F2%21.............)
![=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............](https://tex.z-dn.net/?f=%3D8%2F%28-4%29-8%2F%28-4%29%5E%7B2%7D%20%28-4%29%28x%2B4%29%2F1%21%2B%20%2024%2F%28-4%29%5E%7B3%7D%20%28-4%29%28x%2B4%29%5E%7B2%7D%2F2%21.............)
=-2+2(x+4)/1!-24/16
/2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Learn more about taylor series at brainly.com/question/23334489
#SPJ4
293 tens and 4 ones
<em>Explanation:
</em>If you have 293 tens you have 2930 already.
293*10 = 2930
Now you are only missing 4,
4*1 = 4
so you can use 4 ones
Your answer is 3x^2+14x+2 / x^3+5x^2+4x