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zhenek [66]
3 years ago
12

The graph below shows the solution set of which inequality

Mathematics
1 answer:
Alborosie3 years ago
4 0
Wheres the graph
???i don’t see no graph to answer
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Given that the hypotenuse of this right triangle is 25 cm long and that tan(Θ) = 3 Find the values of x and y, accurate to the n
saveliy_v [14]
The wording of this problem indicates that there was an illustration.  Could you possibly share that illustration?

Working without an illustration:

If tan theta = 3, then tan theta = opp/adj = 3/1.  This tells us that the opp side is 3 times as long as is the adj. side.  Let x be the shorter side, i. e., let x represent the adjacent side; then y is the longer side and represents the opposite side.

Then y = 3x (the opp side is 3x the adj side in length).

Applying the Pyth. Thm.    a^2 + b^2 = c^2,

x^2 + (3x)^2 = hyp^2 = (25 cm.)^2

So x^2 + 9x^2 = (625 cm^2)

10x^2 = 625 cm^2, or x^2 = (625 cm^2) / 10 = 62.5 cm^2

x = 7.91 cm.  Therefore, y = 3(7.91) = 23.72 cm.

We were supposed to round off these answers to the nearest 10th cm.
Therefore, x = 7.9 cm and y = 23.7 cm

Would that be A, B, C or D?
4 0
3 years ago
Read 2 more answers
FSA Mathematics Practice Test Questions
Luda [366]
There is no number line shown...
Brainliest would be nice
8 0
3 years ago
Two glasses of milk and 3 snack bars have a total of 62 carbohydrates, and 3 glasses of milk and 2 snack bars have a total of 58
ludmilkaskok [199]

Step-by-step explanation:

2+3=5

58+62=120

120÷5=24

so 24 carbohydrates are in one glass of milk

7 0
3 years ago
Someone please help, this is my last resort
dolphi86 [110]

Answer:

34 5/8

Step-by-step explanation:

you just add all the numbers on the left and the two drawer numbers then boom!!

5 0
3 years ago
The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.
galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439    

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}

a) P(No high level of contamination)

We put x = 0, in the formula.

P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0
3 years ago
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