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GREYUIT [131]
2 years ago
15

How do i solve step by step s+2 1/2s+20=48 ?

Mathematics
2 answers:
sammy [17]2 years ago
8 0
S+(2+1/2)s+20=48

2/2s+5/2s=48-20

7/2s=28

7s=28*2=2(20+8)=40+16

7s=56

s=56/7

s=8
Anuta_ua [19.1K]2 years ago
6 0
s+2\frac{1}{2}s+20=48\\\\
3,5s+20=48\ \ \ \ | subtract\ 20\\\\
3,5s=28\ \ \ \ | divide\ by\ 3,5\\\\
s=8\\\\
Solution\ is\ s=8.
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Use the inequalities to answer the following question
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Answer:

C, E, and F

Explanation:

There are two ways to answer this question. First, you could simply input each answer into both equations to see which one works but that would take quite a long time.

A better way is to simply solve each equation for x.

You could rewrite

2x + 7 < -3

as

2x + 7 = -3

and solve:

Subtract 7 from both sides

(2x + 7) -7 = (-3) - 7\\2x = -10

Now divide both sides by 2

\frac{2x}{2}  = \frac{-10}{2}\\x = -5

Now we can simply replace the equals sign with the inequality

x < -5

Where you can run into trouble is if you have to multiply or divide by a negative number across the equation, you must flip the inequality sign. It's best to leave it there to remind you, but I switched it out just to show that it's no different than a typical algebraic equation.

Now, we know that x can be any value less than -5. Let's find out the same thing for the second equation:

x - 8 + 3x < -4\\(x + 3x) -8 < -4\\4x - 8 < -4\\(4x - 8) + 8 < (-4) + 8\\4x < 4\\\frac{4x}{4} < \frac{4}{4}\\x < 1

Now we know that x must be less than 1 for the second equation. So, now we can choose the answers that are both less than -5 and less than 1.

These answers are:

C. -10

E. -8.24

and

F. -15/2 which is -7.5

NOTE: -5 is equal to but not less than -5 so G is not included.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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9514 1404 393

Explanation:

<u>Part B</u>:

Draw an open circle at x=5. Shade that portion of the number line that exists to the right of the open circle. The solution set is the shaded portion of the number line.

__

<u>Part C</u>:

Any value from the shaded portion of the number line can be used to check the inequality is true. The value at the open circle, or any value to the left of it can be used to check that the inequality is false. For example, one might use values of -5, 5, and 10. Choosing values that are multiples of 5 can make the arithmetic easier.

<u>x = -5 (expect false)</u>

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<u>x = 5 (expect false)</u>

  -2/5(5) < -2

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