Question

HELP WITH THIS QUESTION NEED HELP ASAP GIVING BRAINLIST!!!!

Answer 1

Answer:

1. $14\geq 3x$

The maximum number of rides he could go on is 4.

2. $39\geq 11x$

Step-by-step explanation:

He has a total of $19 to spend. Therefore we can say that whatever we are going to spend has to be less than or equal to $19.

$19\geq x$

She paid $5 for admission

$19\geq 5$

Rides cost $3 each. (Let x be the number of rides)

3x (three dollars for every ride x)

Add this to the original inequality.

$19\geq 5+3x$

Since we are asked to find the number of rides she can ride, solve for x:

Start by subtracting 5.

$19-5\geq 3x$

Combine like terms;

$14\geq 3x$

Divide by 3.

$\frac{14}{3}\geq x$

Divide.

14/3=4.6

12

------

 20

  18

 -------

    20

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We conclude that the maximum number of rides he could go on is 4

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Amanda has $40 to spend. Again, this means she can spend a maximum of 40. So, anything (x) has to be less than or equal to 40 ($40\geq x$)

She wants to buy a pair of flowers for $1

$40\geq 1$

The rest of the money will be spent on lily flowers. Each lily flower costs $11. Again, multiply 11 by the number of lily flowers, which we don't know so we'll call it x (11x)

Add it to the inequality

$40\geq 1+11x$

Solve for x; begin by subtracting 1

$40-1\geq 11x$

Combine like terms;

$39\geq 11x$

Divide by 11

$\frac{39}{11}\geq x$

Answer 2

Answer:

1. he can go up to 4 rides

2. she can buy 3 flowers

Step-by-step explanation:

1. 19 >= 5+ 3x

19 - 5 >= 3x

14 >= 3x

If you solve this you can get 4 and balance 2

2. 40 >= 2 + 11x

38 >= 11x

If you solve this you can get 3 and balance 5