Answer:
(9, 6)
Step-by-step explanation:
<u>Midpoint formula is:</u>
- x = (x₁ + x₂)/2
- y = (y₁ + y₂)/2
<u>Having coordinates of one end- and midpoint </u>(-5, 12) <u>and</u> (2, 9)<u>:</u>
- x₁ = -5, y₁ = 12
- x = 2, y = 9
<u>we get the coordinates of the missing endpoint with coordinates</u> (x₂, y₂):
- x₂ = 2x - x₁ = 2*2 - (-5) = 4 + 5 = 9
- y₂ = 2y - y₁ = 2*9 - 12 = 18 - 12 = 6
<u>So the missing point is</u>: (9, 6)
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
Answer:
for 9
Step-by-step explanation:
john grabs a piece of kitchen twine, he grabs the whole length of 8 ft. He 1/2 off. He then cuts another half of on each piece of twine. How many pieces of kitchen twine does john have?
Answer:
The answer to your question is length = 6 in, # of pieces = 8
Step-by-step explanation:
Data
2 sandwiches one of 18 in and other of 30 in
cut into equal sections
To solve this problem, use the greatest common divisor, so find the prime factors of both numbers.
18 30 <u>2 </u> Only 2 and three are common factors, then
9 15 <u>3 </u> 2 x 3 = 6
3 5 3
1 5 5
1
The length of the sections will be 6 inches
How many sections will be? in the first 18/6 = 3 in the second 30/6 = 5
total = 8
Answer:
A is correct pls give likes and brainliest (I actually checked the work sheet for answer key)
