<h3>The solution as an ordered pair is (x,y) = (2,2)</h3><h3>x = 2 and y = 2 pair up together.</h3>
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Work Shown:
4x+2y = 12
4x+2( y ) = 12
4x+2( 2x-2 ) = 12 ... replace y with 2x-2
4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule
4x+4x-4 = 12
8x-4 = 12
8x-4+4 = 12+4 ... add 4 to both sides
8x = 16
8x/8 = 16/8 ... divide both sides by 8
x = 2 is the first part of the answer
Use x = 2 to find y
y = 2x-2
y = 2(2)-2 ... replace x with 2
y = 4-2
y = 2 is the second part of the answer
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
the answer is 8
Step-by-step explanation:
1/2(8 + 4) = 6
0.5(8 + 4) = 6
(4 + 2) = 6
6 = 6
Answer:
The answer is 7x-25
Step-by-step explanation:
(3x+5)+(4x-30)
=3x+4x+5-30
=7x-25
Answer: g(0) = 2
Step-by-step explanation:
g(x)=3x+2
g(0)=3(0)+2
=2