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erma4kov [3.2K]
3 years ago
14

Solution to the compound inequality –6 ≤ 2 + 6 ≤ 6 -12≤x≤0 6≤x≤6 -6≤x≤0 0≤x≤6

Mathematics
1 answer:
Ket [755]3 years ago
5 0
-6 < = 2x + 6 < = 6....subtract 6 from all sections
-6 - 6 < = 2x + 6 - 6 < = 6 - 6...simplify
-12 < = 2x < = 0...divide all sections by 2
-12/2 < = (2/2)x < = 0/2....simplify
-6 < = x < = 0...by the way, I cant put the line under the inequality sign to show the equal sign...so I just put the = sign with the inequality sign
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3 years ago
A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour how many
Burka [1]

Answer:

2 1/4 times

Step-by-step explanation:

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour. how many times as long in the morning did he work in the afternoon

Note that:

1 hour = 60 minutes

In the moring he worked 2/5 of an hour.

= 2/5 × 60 minutes

= 24 minutes

In the afternoon he worked for 9/10 of an hour

Hence:

9/10 × 60 minutes

= 54 minutes

How many times as long in the morning did he work in the afternoon?

This is calculated as number of minutes worked in the afternoon ÷ Number of minutes worked in the morning

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4 0
3 years ago
(1) -3x-4y+11z from-9y+6z-3x <br>(2) 3x⁴-4x³+7x-2 from 9-7x⁴+6x³-2x²-11x​
romanna [79]

Answer:

1) 5y + 5z

2) 10x⁴ - 10x³ + 2x² + 18x - 11

Step-by-step explanation:

Given the subtraction of the following polynomial expressions:

<h2>(1) -3x - 4y + 11z from -9y + 6z - 3x</h2>

In order to make it easier for us to perform the required mathematical operations, we must first rearrange the terms in the <em>subtrahend</em> by alphabetical order.

-3x - 4y + 11z  

-3x - 9y + 6z  ⇒ This is the <u><em>subtrahend</em></u>.

Now, we can finally perform the subtraction on both trinomials:

\displaystyle\mathsf{\left \ \quad\:\:\:\:{-3x - 4y + 11z} \atop -\quad{\underline{-3x - 9y + 6z\:\:\underline}} \right.}

In the <em>subtrahend</em>, the coefficients of x and y are both negative. Thus, performing the subtraction operations on these coefficients transforms their sign into positive.  

\displaystyle\mathsf{\left \ \quad\:\:\:\:{-3x - 4y + 11z} \atop -\quad{\underline{-3x - 9y + 6z\:\:\underline}}\right.} \\\qquad\sf {\qquad\:\:\:0x\:+\:5y\:+5z

The difference is: 5y + 5z.

<h2>(2) 3x⁴- 4x³ + 7x - 2 from 9 - 7x⁴ + 6x³- 2x² - 11x​</h2>

Similar to the how we arranged the given trinomials in Question 1, we must rearrange the given polynomials in descending degree of terms before subtracting like terms.

3x⁴- 4x³ + 7x - 2           ⇒  Already in descending order (degree).

9 - 7x⁴ + 6x³- 2x² - 11x​   ⇒  -7x⁴ + 6x³- 2x² - 11x​ + 9

In subtracting polynomials, we can only subtract <u>like terms</u>, which are terms that have the same variables and exponents.  

\displaystyle\mathsf{\left \ \quad\:\:{3x^4\:-4x^3\:+\:0x^2\:+\:7x\:-\:2} \atop -\quad{\underline{-7x^4\:+6x^3\:-2x^2\:-11x\:+\:9 \:\:\underline}}\right.}  

In the <u><em>minuend</em></u><em>, </em>I added the "0x²" to make it less-confusing for us to perform the subtraction operations.  

The same rules apply in terms of coefficients with negative signs in the subtrahend, such as: -7x⁴, - 2x², and - 11x​ ⇒  their coefficients turn into positive when performing subtraction.  

\displaystyle\mathsf{\left \ \quad\:\:{3x^4\:-4x^3\:+\:0x^2\:+\:7x\:-\:2} \atop -\quad{\underline{-7x^4\:+6x^3\:-2x^2\:-11x\:+\:9 \:\:\underline}}\right.} \\\qquad\sf {\qquad\:\:10x^4-10x^3+2x^2+18x\:-11  

Therefore, the difference is: 10x⁴ - 10x³ + 2x² + 18x - 11.

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

The diagram shows lines passing through the points of two equations.

We will determine the points through which the lines pass through on the graphs.

Looking at the line on the right hand side of the graph, the slope is

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y2= 0, y1 = 4

x2 = 3, x1=0

Slope, m = (0-4)/3-0

Slope = -4/3

Recall the equation of a straight line is y = mx + c

Where c is the intercept.

So the equation is y

y = -4x/3 + 4

Looking at the line on the left hand side of the graph, the slope is

(y2-y1)/x(2-x1) where

y2= 0, y1 = 2

x2 = -1, x1 =0

Slope, m = (0-2)/-1-0

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The equation

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So the equations are

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