1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slega [8]
2 years ago
14

ABC Bookstore sells one customer 12 used books and 4 new books for $136.

Mathematics
1 answer:
Natalka [10]2 years ago
5 0

Answer:

n=6 u=28/3

Step-by-step explanation:

system of equations

You might be interested in
Come someone please help me and explain this
OLga [1]
Change in y over change in x
7 0
3 years ago
If you answer my question can you please tell me how to do it step by step.​
hichkok12 [17]

Answer:

Depends

Step-by-step explanation:

It depends because I don't know if I'm strong on the material you're asking about.

5 0
3 years ago
Which of the following is the vertical asymptote for the graph below?
forsale [732]

Answer:

C

Step-by-step explanation:

Vertical asymptotes are always in the form x = ?

If you look at the dotted line, it lands on 2.  Because it's a vertical line, the asymptote is going to be x = 2

4 0
2 years ago
Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17
V125BC [204]

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}

Cramer's rule says that

x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}

where x_i is the solution for i-th variable, and \mathbf A_i is a modified version of \mathbf A with its i-th column replaced by \mathbf b.

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}

\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}

\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))

\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120

The modified matrices and their determinants are

\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240

\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360

\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480

Then by Cramer's rule, the solution to the system is

x = \dfrac{-240}{-120} \implies \boxed{x = 2}

y = \dfrac{360}{-120} \implies \boxed{y = -3}

z = \dfrac{-480}{-120} \implies \boxed{z = 4}

5 0
1 year ago
Find the interquartile range for this set of data.
yawa3891 [41]

Answer:

96

Step-by-step explanation:

198 − 102 = 96

6 0
3 years ago
Other questions:
  • Is my answer correct?<br> 2 1/4 + 1/4 = 2 1/2
    7·1 answer
  • What is the answer
    10·2 answers
  • Express 17.1 6 as a mixed number in lowest terms
    11·1 answer
  • If Target Corp. (TGT) recently earned a profit of $6.07 earnings per share and has a P/E ratio of 16.5. The dividend has been gr
    6·1 answer
  • See if you can put these inventions in the correct order, most recent to oldest!
    14·2 answers
  • 6th grade math... anybody can help ?! :)
    12·1 answer
  • A set of test scores is normally distributed with a mean of 78 and a standard deviation of 4.5. Dwayne scored 87 on the test. Wh
    6·2 answers
  • What is the circumference of the circle below?​
    6·1 answer
  • Design specifications require that a key dimension on a product measure 100 /- 10 units. A process being considered for producin
    15·1 answer
  • Please I need help!!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!