Answer:
The sign of each y-coordinate changed.
Step-by-step explanation:
This was a reflection over the x-axis.
If you look at point F, it is (-5, -1) the corresponding point F' is (-5,1). Notice the numerical values of x and y are the same, but the sign of y flipped from negative to positive. The other four points all follow the same pattern.
<span>619.473970397 here is the square root</span>
First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:

The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:

and

Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
Answer:
Well the answer is the first one 3 (5 x) and 15x
Step-by-step explanation:
Because it is the same thing as (5 x) 3. The numbers just changed the positions.
And 15x because you can multiply the first 5 times 3 and that is equal with 15 and then you put the x at the end. 15x
Answer:
Line JK passes through points J(-4,-5) and K(-6, 3).
Line JK has form of y = mx + b
=> -5 = -4m + b
=> 3 = -6m + b
Subtract 2nd equation from 1st equation:
=> -8 = 2m
=> m = -4
Substitute back m = -4 into 1st equation:
=> -5 = -4(-4) + b
=> b = -21
Hope this helps!
:)