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-BARSIC- [3]
3 years ago
7

What point on the graph of y = 0.5f(x) corresponds to (4, 16)? Explain.

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

We are given a coordinate (4,16).

Where first coordinate is the value of x and second coordinate is the value of y for the function y=f(x).

We need to find the value of given point (4,16) for function y= 0.5f(x).

Here function f(x) is being multiplied by 0.5.

On multiplying 0.5 by y, it will effect the value of y only. It does not effect value of  x . Because x value is still x. Only function f(x) is being multiplied by 0.5.

Therefore, y= 0.5f(4) = 0.5 * 16 = 8.

So, (4,8) is the point on the graph of y = 0.5f(x) corresponds to (4, 16).

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Answer:

44,55,000 cubic meters of treasure could fit the pyramid.

Step-by-step explanation:

We are given the following in the question:

Base measure = 450 meters

Height  = 66 meters

The volume of the pyramid is given by:

V = \dfrac{AH}{3}

where A is the ares of the base and H is the height of the pyramid.

Putting values, we get,

V = \dfrac{1}{3}\times (450\times 450) \times 66\\\\V = 4455000\text{ cubic meters}

Thus, 4455000 cubic meters of treasure could fit the pyramid.

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3 years ago
You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Right and solv
slavikrds [6]

Answer:

x = 33

Step-by-step explanation:

Given

Students = 28

Brownies = 23

Brownies = 2\ per\ student

Required

Determine the number of brownies left

If:

Brownies = 2\ per\ student

and there are 28 students

Then:

Total\ Brownies = 2 * 28

Total\ Brownies = 56

To determine the number of brownies left, we have:

Total\ Brownies = Brownies\ Made + Brownies\ Left

56 = 23 + x

Reorder

x + 23 = 56

Collect Like Terms

x = 56 - 23

x = 33

<em>Hence, there are 33 brownies left</em>

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4 years ago
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Step-by-step explanation:

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Graph the function: y=x-5​
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Step-by-step explanation:

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3 years ago
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kap26 [50]

Answer:   \bold{\dfrac{27x^2y^3}{16}}

<u>Step-by-step explanation:</u>

\dfrac{(3x^2y^5)^3}{(2xy^3)^4}\\\\\\=\dfrac{3^3\cdot x^{2\cdot 3}\cdot y^{5\cdot 3}}{2^4\cdot x^4\cdot y^{3\cdot 4}}\\\\\\=\dfrac{27\cdot x^6\cdot y^{15}}{16\cdot x^4\cdot y^{12}}\\\\\\=\dfrac{27\cdot x^{6-4}\cdot y^{15-12}}{16}\\\\\\=\dfrac{27\cdot x^2\cdot y^3}{16}

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3 years ago
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