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Dimas [21]
3 years ago
15

Cindy has 34 meters of fencing. She

Mathematics
1 answer:
inn [45]3 years ago
8 0
Her within reach work be 54 percent with the chance of getting to work
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0.2(x + 1) + 0.5x = -0.3(x - 4)?
andreyandreev [35.5K]

Answer:

x=1.....................

7 0
3 years ago
What is the value of the expression 9 + (fraction 1 over 2)4 ⋅ 48?
lyudmila [28]

Answer -> (12) I'm very late haha but hopes this helps!

3 0
3 years ago
Express 0.361 recurring as a fraction.<br> (only the 61 recurs)
Oduvanchick [21]

9514 1404 393

Answer:

  179/495

Step-by-step explanation:

When the repeating decimal starts at the decimal point, the repeating digits can be turned into a fraction by putting them over the same number of 9s. That is, 0.61616161... is equivalent to 61/99.

Here, the repeating part is 1/10 that value, so is 61/990. This is added to the non-repeating part, which is 0.3 = 3/10.

Then the entire decimal is ...

  0.361_61 = 3/10 + 61/990 = (297 +61)/990 = 358/990 = 179/495

7 0
2 years ago
Quantity of 42.1% of 375.4
Stells [14]
That is =
(42.1/100)*37.5
=(421/1000)*(375/10)
=(157875/10000)
=15.7875
=15.8
=16
8 0
3 years ago
Which additional fact proves that ΔRST and ΔWXY are congruent if ∠T ≅ ∠Y and RT ≅ WY?
sergejj [24]

Answer:

Hence, option A is correct.

Step-by-step explanation:

We are asked to find the fact such that ΔRST and ΔWXY are congruent.

Since, we are given: ∠T ≅ ∠Y  and  RT ≅ WY.

we are given the following assumptions:

∠W = x + 5  

∠X = 3x - 9


∠Y = 2x + 4

as we are given one angle congruent and one side congruent so in order to prove two triangles are congruent we just need to show that one more pair of angles are congruent.

so from the two triangle we could have that ∠W≅∠R

and ∠X≅∠S

Now we will go by options:

A)

if ∠S=2x+20 then as ∠X≅∠S.

3x-9=2x+20

x=29

∠S=∠W=78°.

B)

if ∠R = 2x + 20 then as  ∠W≅∠R

⇒  x+5=2x+20

⇒ x= -15 which is not possible as it will make measure of angle W negative (x+5= -15+5= -10)

C)

if ∠S=2x^2+5 then as  ∠X≅∠S.

⇒ 3x-9=2x^2+5

⇒ 2x^2-3x+14=0

on solving this quadratic equation we will get complex zeros.

Hence, option (C) is not correct.

D)

if ∠R =  2x

^2

+ 5 then as ∠W≅∠R.

⇒ x+5=

2x

^2

+ 5

⇒ 2x^2-x=0

⇒ x(2x-1)=0

either x=0 or x=1/2 which is not  possible.

because by putting this x value in all the angles we see that sum of all the angles of a triangle is not equal  to 180°

Hence, option D is not possible.

Hence, option A is correct.



4 0
3 years ago
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